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WINSTONCH [101]
2 years ago
8

A regular polygon has a perimeter of 40 cm and a apothem of 6 cm. find the polygons area

Mathematics
1 answer:
Anestetic [448]2 years ago
3 0

Answer:

a = 120 cm²

Step-by-step explanation:

n = number of sides

edge length

40/n

divide the polygon into n congruent triangles

a = (1/2)(edge * apothem) * number of triangles

a = (1/2)(40/n)(6) * n

n cancels out

a = (1/2)(40)(6)

a = 120 cm²

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<h3><u>Solution</u></h3>

<u>Given </u><u>:</u><u>-</u>

  • Perimeter of rectangle = 72 cm
  • The length is 3 more than twice the width.

<u>F</u><u>i</u><u>n</u><u>d</u><u> </u><u>:</u><u>-</u>

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<h3 /><h3><u>Explantion</u></h3>

<u>Using </u><u>Formula</u>

\boxed{\underline{\tt{\red{\:(perimeter_{rectang}\:=\:2\times (Length+Width)}}}}

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<u>According</u><u> to</u><u> question</u><u>,</u>

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<u>Again,</u>

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<u>Subtract</u><u> </u><u>equ(</u><u>1</u><u>)</u><u> </u><u>&</u><u> </u><u>equ(</u><u>2</u><u>)</u>

==> y + 2y = 36 - 3

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<u>keep </u><u>in </u><u>equ(</u><u>1</u><u>)</u>

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