I got:
-2(2f-3g)
explanation:
used communicative property
The range of the equation is 
Explanation:
The given equation is 
We need to determine the range of the equation.
<u>Range:</u>
The range of the function is the set of all dependent y - values for which the function is well defined.
Let us simplify the equation.
Thus, we have;

This can be written as 
Now, we shall determine the range.
Let us interchange the variables x and y.
Thus, we have;

Solving for y, we get;

Applying the log rule, if f(x) = g(x) then
, then, we get;

Simplifying, we get;

Dividing both sides by
, we have;

Subtracting 7 from both sides of the equation, we have;

Dividing both sides by 2, we get;

Let us find the positive values for logs.
Thus, we have,;


The function domain is 
By combining the intervals, the range becomes 
Hence, the range of the equation is 
Answer:
E(29/4,3)
Step-by-step explanation:
Given that,
Segment CD has point E located on it such that CE:ED = 3:5
The coordinates of C and D are (5, -6) and (11,18) respectively.
We need to find the coordinates of E. Let the coordinates are (x,y). Using section formula to find it as follows :

So, the coordinates of E are (29/4,3).
Answer:
7x² + 9x + 6y
Step-by-step explanation:
7x² + 4x + 5x + 8y - 2y
Answer: t= 4 seconds
Maximum height = 256 feet
Step-by-step explanation:
The height of the object projected upwards after t seconds is given by
s(t)=-16t^2+128t.
The expression is a quadratic equation. When this equation is plotted on a graph, height against time, it takes the shape of a parabola whose vertex represents the maximum height attained by the object.
To get the value of t at the maximum height,
t = -b/2a
From the equation,
a = -16
b = 128
t = -128/-2×-16
= -128 /- 32= 4
it will take 4 seconds to reach its maximum height
To find maximum height attained, put t= 4 in the equation
s(t)=-16t^2+128t
S = -16× 4^2 + 128×4
S = -256+512
S = 256 feet