Answer:
For both sets of data, the median is equal to the mean.
The interquartile range (IQR) is greater for M's classes than J's classes.
Step-by-step explanation:
<u>J's Classes:</u>
23, 25, 27, 28, 32
Median: 27
Mean: 27
Mean Absolute Deviation: 2.4
Interquartile Range: 3
<u>M's Classes:</u>
20, 24, 26, 29, 31
Median: 26
Mean: 26
Mean Absolute Deviation: 3.2
Interquartile Range: 5
8 7/16 - (-2 4/9) =
8 7/16 + 2 4/9 =
8 7/16 = 135/16 = 1215/144
2 4/9 = 22/9 = 352/144
1215/144 + 352/144 = 1567/144 =10 127/144
The answer is a because 552.50 x .12 is 66.30. 66.30 minus 552.50 is 486.50 and that divided by 7 is 69.45
Considering the perimeter (P)
where b is the base and h is the height, then
Being the area (A)
