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lorasvet [3.4K]
3 years ago
14

A carpet manufacturer is inspecting for flaws in the finished product. If there are too many blemishes, the carpet will have to

be destroyed. He finds the number of flaws in each square yard and is interested in the average number of flaws per 10 square yards of material. The sample mean, x, for the 10 square yards will have what type of distribution?a. normal distributionb. neither of thesec. binomial distribution
Mathematics
1 answer:
balandron [24]3 years ago
7 0

Answer:

Neither binomial nor normal distribution

Step-by-step explanation:

In binomial distribution Sumner of trials are fixed and there is only two outcomes either success or failure

But in this question there are no fixed trials and outcomes is not proper so this is not a binomial distribution.

In normal distribution there is information of mean and variance which is also not give in the question so it is also nit a normal distribution

So it is neither binomial nor normal distribution

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Answer:

-8x^2+8(10x)-72

When x=18

-8(18×18-(10×18)+9)

-72(36-20+1)

17×(-72)

=-1224

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Mr. Barrett bought a new battery for his car. The battery cost $72. Since batteries are a taxable item, he had to pay a sales ta
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Answer:

$77 and 40¢

Step-by-step explanation:

7.5 percent of $72 is $5.4 so you would add $5.4 to $72 which makes $77.40.

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A Man receives 7½% commission on his sales
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3 years ago
Which measures are accurate regarding triangle JKL? Check all that apply.
mixas84 [53]

Answer:

Option (1), (3) and (6) is correct.

m∠K = 84° , k ≈ 3.7 units and KL ≈ 3.2 units.

Step-by-step explanation:

  Given : ∠J = 58° , ∠L = 38°  and length of side JK = 2.3 units.

We need to check all the options and choose that follows.

First we find the measure of ∠K

Using angle sum property , Sum of angles of a triangle  is 180°

⇒ ∠J + ∠k + ∠L = 180°

⇒ 58° + ∠k + 38° = 180°

⇒  ∠k + 96° = 180°

⇒  ∠k   = 180° - 96°

⇒  ∠k   = 84°

Also using sine rule on ΔJKL , we get,

\frac{KL}{\sin J}=\frac{JL}{\sin K}=\frac{JK}{\sin L}

Substitute the values, we get,

\frac{KL}{\sin 58^{\circ}}=\frac{k}{\sin 84^{\circ}}=\frac{2.3}{\sin 38^{\circ}}

Consider the last two ratios, we have,

\frac{k}{\sin 84^{\circ}}=\frac{2.3}{\sin 38^{\circ}}

{k}=\frac{2.3}{\sin 38^{\circ}}\times {\sin 84^{\circ}}

On solving we get,

{k}=3.71

Also, now consider the first and last ratio, we get,

\frac{KL}{\sin 58^{\circ}}=\frac{2.3}{\sin 38^{\circ}}

{KL}=\frac{2.3}{\sin 38^{\circ}}\times {\sin 58^{\circ}

{KL}=3.16

Thus, k ≈ 3.7 units and KL ≈ 3.2 units.

Option (1), (3) and (6) is correct.

5 0
4 years ago
Read 2 more answers
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murzikaleks [220]
I think the answer should be 50
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3 years ago
Read 2 more answers
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