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JulijaS [17]
3 years ago
13

A village wishes to measure the quantity of water that is piped to a factory during a typical morning. A gauge on the water line

gives the flow rate (in cubic meters per hour) at any instant. The flow rate is about 100 m3/hr at 6 am and increases steadily to about 280 m3/hr at 9 am. Using only this information, give your best estimate of the total volume of water used by the factory between 6 am and 9 am.
Mathematics
1 answer:
anzhelika [568]3 years ago
3 0

Answer:

570 m³

Step-by-step explanation:

The volume of water is the product of flow rate of water and the time taken. We are to get the volume of water used between 6 am and 9 am, that is for 3 hours (9 - 6).

We are given the flow rate at 6 am and the flow rate at 9 am, but this flow rate changes between 6 am and 9 am. To get the estimate of the water used, Let us assume that it flows at the same flow rate as it was at 6 am throughout, hence:

V_L= 100 m^3/h * 3h=300\ m^3

Also, let us assume that it flows at the same flow rate as it was at 9 am throughout, hence:

V_R= 280 m^3/h * 3h=840\ m^3

To get the best estimate of the total volume, let us find the average of the two values, hence:

Volume=\frac{V_L+V_R}{2} =\frac{300+840}{2}=570\ m^3

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masha68 [24]
The answer to the first B one is horizontal translation 1 to the right because the -1 is inside the quantity.
2nd g(x)=3x^2+8
4 0
3 years ago
Find the smallest positive integer k such that 3240/k is a square number
sashaice [31]

Answer:

10

Step-by-step explanation:

First, factorize the number 3,240:

3,240=2\cdot 1,620=2\cdot 2\cdot 810=2\cdot 2\cdot 2\cdot 405=2\cdot 2\cdot 2\cdot 2\cdot 5\cdot 81=2^3\cdot 5\cdot 9^2

So,

3,240=2^2 \cdot 2\cdot 5\cdot 9^2=18^2\cdot 10

Now consider the fraction

\dfrac{3,240}{k}=\dfrac{18^2\cdot 10}{k}

If k = 10, then

\dfrac{3,240}{k}=\dfrac{18^2\cdot 10}{10}=18^2

is a square number.

For all k < 10, the fraction tex]\dfrac{3,240}{k}[/tex] is not a square number (this follows from factorization).

Or you can simply check the values of the fraction for all k < 10:

  • k = 1, \dfrac{3,240}{1}=3,240 is not a square number;
  • k = 2, \dfrac{3,240}{2}=1,620 is not a square number;
  • k = 3, \dfrac{3,240}{3}=1,080 is not a square number;
  • k = 4, \dfrac{3,240}{4}=810 is not a square number;
  • k = 5, \dfrac{3,240}{5}=648 is not a square number;
  • k = 6, \dfrac{3,240}{6}=540 is not a square number;
  • k = 7, \dfrac{3,240}{7} is not a square number;
  • k = 8, \dfrac{3,240}{8}=405 is not a square number;
  • k = 9, \dfrac{3,240}{9}=360 is not a square number.
5 0
3 years ago
13x = 79 ? Can somebody explain #9 b. PLEASE. Please solve using the system of linear equations by elimination.I would love it i
strojnjashka [21]
8x + 2y = 44
5x + 2y = 35

Since 2y is already common, there is no need for multiplication. Just reverse the signs on the equation.

Like this; 

8x + 2y = 44
-5x - 2y = -35

All the additions become subtractions and vice versa.

-2y and +2y get cancelled.

Leaving;

8x = 44
-5x = -35

Now, subtract again. 

8x - 5x = 3x

44 - 35 = 9

So;

3x = 9

x = 9 / 3

x = 3

We found 'x' and now we have to find 'y'.

Just substitute. 

[8 x 3] + 2y = 44

24 + 2y = 44

2y = 44 - 24

2y = 20

y = 20 / 2

y = 10

Now, we re-check;

[8 x 3] + [2 x 10] = 44

24 + 20 = 44

Explaining the error for #9b is simply doing the whole sum. 

Hope this helped! :) I tried my best to explain. 

7 0
3 years ago
On your tenth birthday, you received 500 which you invested at 9.5% interest, compounded annually. your investment is worth $250
igomit [66]
Compounded once a year: A=P(1+r)^t
2500=500(1+0.095)^t
1.095^t=5
because the unknown number is an exponent, use log to find the unknown:
log(1.095^t)=log5
tlog1.095=log5
t=log5/log1.095
use your calculator, t=17.734
so this person is about 28 years old.
6 0
2 years ago
What is the answer of 1 1/6 + 3 5/8<br><br> A. 5 ½<br> B. 5 ⁵⁄₁₄<br> C. 1 ⅙<br> D. 4 ¹⁹⁄₂₄
solmaris [256]
D. 4 19/24
(WORK BELOW)

5 0
2 years ago
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