Answer:
9m^2 - 12mn + 4n^2
Step-by-step explanation:
Total number of computers in sample = 72 + 112 + 711 = 895.
P(LQ) = 72/895 = 0.08
P(MQ) = 112/895 = 0.125
P(HQ) = 711/895 = 0.794
Answer:
The interval from the sample of size 400 will be approximately <u>One -half as wide</u> as the interval from the sample of size 100
Step-by-step explanation:
From the question we are told the confidence level is 95% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the 95% confidence interval is dependent on the value of the margin of error at a constant sample mean or sample proportion
Generally the margin of error is mathematically represented as
Here assume that
is constant so

=> 
=> 
So let
and 
=> 
=> 
=> 
So From this we see that the confidence interval for a sample size of 400 will be half that with a sample size of 100
Since there are two events happening simultaneously (windy and no sun), we can apply the concept of conditional probability here.
P(A|B) = P(A∩B)/P(B)
where it means that given B is happening, the probability that A is happening as well is the ratio of the chance for A and B to happen simultaneously over the chance of B to happen.
For our case, this can be interpreted as
P(A|B): it is the probability that it is windy (A) GIVEN that there is no sun (B)
P(A∩B) : chance of wind and no sun
P(B) : chance that there is no sun tomorrow
The chance of P(A∩B) is already given as 20% or 0.20. Since there is 10% or 0.10 chance of sun, then chances of having no sun tomorrow is (1-0.10) = 0.90.
Thus, we have P(A|B) = 0.2/0.9 ≈ 0.22 or 22%.
So, answer is B: 22%<span>.</span>