Answer:
![\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccc%7D%7BMidpoint%7D%20%26%20%7BClass%7D%20%26%20%7BFrequency%7D%20%26%20%7B64%7D%20%26%20%7B63-65%7D%20%26%20%7B1%7D%20%20%26%20%7B67%7D%20%26%20%7B66-68%7D%20%26%20%7B11%7D%20%26%20%7B70%7D%20%26%20%7B69-71%7D%20%26%20%7B8%7D%20%26%7B73%7D%20%26%20%7B72-74%7D%20%26%20%7B7%7D%20%20%26%20%7B76%7D%20%26%20%7B75-77%7D%20%26%20%7B3%7D%20%26%20%7B79%7D%20%26%20%7B78-80%7D%20%26%20%7B1%7D%5C%20%5Cend%7Barray%7D)
Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:
![M = \frac{1}{2}(Lower + Upper)](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28Lower%20%2B%20Upper%29)
Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:
![M = \frac{1}{2}(63 + 65) = 64](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2863%20%2B%2065%29%20%3D%2064)
Class 66 - 68:
![M = \frac{1}{2}(66 + 68) = 67](https://tex.z-dn.net/?f=M%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2866%20%2B%2068%29%20%3D%2067)
When the computation is completed, the frequency distribution will be:
![\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccc%7D%7BMidpoint%7D%20%26%20%7BClass%7D%20%26%20%7BFrequency%7D%20%26%20%7B64%7D%20%26%20%7B63-65%7D%20%26%20%7B1%7D%20%20%26%20%7B67%7D%20%26%20%7B66-68%7D%20%26%20%7B11%7D%20%26%20%7B70%7D%20%26%20%7B69-71%7D%20%26%20%7B8%7D%20%26%7B73%7D%20%26%20%7B72-74%7D%20%26%20%7B7%7D%20%20%26%20%7B76%7D%20%26%20%7B75-77%7D%20%26%20%7B3%7D%20%26%20%7B79%7D%20%26%20%7B78-80%7D%20%26%20%7B1%7D%5C%20%5Cend%7Barray%7D)
Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:
![\bar x = 70.2903](https://tex.z-dn.net/?f=%5Cbar%20x%20%3D%2070.2903)
![\sigma = 3.5795](https://tex.z-dn.net/?f=%5Csigma%20%3D%203.5795)
<em>See attachment for result of 1-VarStats</em>
Step-by-step explanation:
she took the 2X and substract 4X-2X
the answer will be 2X=402
Answer:
what does it pass through
Answer is $506.25.
first month is $100,
second month is 100 times 1.5 which is 150.
thirst month is 150 times 1.5 which is 225.
fourth month is 225 times 1.5 which is 337.5
fifth month is 337.5 times 1.5 which is 506.25