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zysi [14]
3 years ago
11

Suppose the discrete random variable X has the probability distribution below:

Mathematics
1 answer:
Talja [164]3 years ago
4 0

(a) P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.11 + 0.52 + 0.19 = 0.82

(b) P(X ≥ 1) = P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.52 + 0.19 + 0.12 + 0.06 = 0.89

(c) µ = 0×0.11 + 1×0.52 + 2×0.19 + 3×0.12 + 4×0.06 = 1.5

(d) σ² = (0²×0.11 + 1²×0.52 + 2²×0.19 + 3²×0.12 + 4²×0.06) - µ² = 1.07

σ = √(σ²) ≈ 1.03

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ABCD is a parallelogram. if side AB=6x-10, side BC=4x-5, and side CD =3x+5, find the value of x
serg [7]

Answer:

x=5

Step-by-step explanation:

If ABCD is a parallelogram, then AB = CD

AB=CD

6x-10 = 3x+5

Subtract 3x from each side

6x-3x -10 = 3x-3x+5

3x-10 = 5

Add 10 to each side

3x-10+10 = 5+10

3x = 15

Divide by 3 on each side

3x/3 =15/3

x=5


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3 years ago
Find the circumference of the circle and round to the nearest tenth
ikadub [295]

Answer:

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2 years ago
10 increased by the quotient of a number and 6 is 15
Makovka662 [10]
<h2>Verbal Phrase to Mathematical Phrase</h2><h3>Answer:</h3>

10 +\frac{n}{6} = 15\\

<h3>Step-by-step explanation:</h3>

Let that number be n.

The quotient of a number and 6 is \frac{n}{6}\\.

"Increased" is just another term for "plus (+)" so 10 increased by The quotient of a number and 6 is 10 + \frac{n}{6}\\

And it tells us that it is 15 so it must be 10 +\frac{n}{6} = 15\\

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According to Masterfoods, the company that manufactures M&amp;M’s, 12% of peanut M&amp;M’s are brown, 15% are yellow, 12% are re
Anna35 [415]

Answer:

Kindly check explanation

Step-by-step explanation:

Given the following :

P(brown) = 12% = 0.12

P(Yellow) = 15% = 0.15

P(Red) = 12% = 0.12

P(blue) = 23% = 0.23

P(orange) = 23% = 0.23

P(green) = 15% = 0.15

A.) Compute the probability that a randomly selected peanut M&M is not yellow.

P(not yellow) = P(Yellow)' = 1 - P(Yellow) = 1 - 0.15 = 0.85

B.) Compute the probability that a randomly selected peanut M&M is brown or red.

P(Brown) or P(Red) :

0.12 + 0.12 = 0.24

C.) Compute the probability that three randomly selected peanut M&M’s are all brown.

P(brown) * P(brown) * P(brown)

0.12 * 0.12 * 0.12 =0.001728

D.) If you randomly select three peanut M&M’s, compute that probability that none of them are blue.

P(3 blue)' = 1 - P(3 blue)

P(3 blue) = 0.23 * 0.23 * 0.23 = 0.012167

1 - P(3 blue) = 1 - 0.012167 = 0.987833

If you randomly select three peanut M&M’s, compute that probability that at least one of them is blue.

P(1 blue) + p(2 blue) + p(3 blue)

(0.23) + (0.23*0.23) + (0.23*0.23*0.23)

0.23 + 0.0529 + 0.012167

= 0.295067

5 0
3 years ago
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