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TiliK225 [7]
3 years ago
9

Solve for all values of x in simplest form. - 2x + 4 + 3 = -4

Mathematics
1 answer:
Kay [80]3 years ago
4 0

Step-by-step explanation:

- 2x + 4 + 3 = -4

-2x+7= -4

-2x= -4-7

-2x= -11

x=-11/-2

x=11/2

x=5.5 (if u want the answer in decimal form)

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Ugo [173]
The answer should be  21/8 hope it helps

7 0
3 years ago
Add one number to each column of the table so that it shows a function
iogann1982 [59]

Answer:

Step-by-step explanation:

y= -1/4x

6 0
2 years ago
Please please please help me with this answer
Sergio039 [100]

Hello,

85 / 12 ≈ 8

Bye ;)

3 0
3 years ago
need some help with geo, could you explain how to do it as well so i know next time not needed but helpful
Setler [38]
You can do this by finding the lengths of RT , RS and ST using the distance formula

RT = sqrt ((0- -5)^2  + (4 - -6)^2)
      = sqrt (5^2 + 10^2)  = sqrt 125

RS =  sqrt ((-3- -5)^2 +  (-2 - -6)^2))
       = sqrt  ( 2^2 + 4^2)  = sqrt 20

ST  = sqrt 125 - sqrt 20

RS / ST  = sqrt 20 / (sqrt 125-sqrt 20)

so the ratio RS:ST = 2:3

Its B
5 0
3 years ago
The distribution of scores on the SAT is approximately normal with a mean of mu = 500 and a standard deviation of sigma = 100. F
ella [17]

Answer:

a. 2.28%

b. 30.85%

c. 628.16

d. 474.67

Step-by-step explanation:

For a given value x, the related z-score is computed as z = (x-500)/100.

a. The z-score related to 700 is (700-500)/100 = 2, and P(Z > 2) = 0.0228 (2.28%)

b. The z-score related to 550 is (550-500)/100 = 0.5, and P(Z > 0.5) = 0.3085 (30.85%)

c. We are looking for a value b such that P(Z > b) = 0.1, i.e., b is the 90th quantile of the standard normal distribution, so, b = 1.281552. Therefore, P((X-500)/100 > 1.281552) = 0.1, equivalently  P(X > 500 + 100(1.281552)) = 0.1 and the minimun SAT score needed to be in the highest 10% of the population is 628.1552

d. We are looking for a value c such that P(Z > c) = 0.6, i.e., c is the 40th quantile of the standard normal distribution, so, c = -0.2533471. Therefore, P((X-500)/100 > -0.2533471) = 0.6, equivalently P(X > 500 + 100(-0.2533471)), and the minimun SAT score needed to be accepted is 474.6653

4 0
3 years ago
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