Answer:
no, there is not enough information to use AAS congruence theorem to prove the triangles are congruent
Answer:
Step-by-step explanation:
Use synthetic division to answer this. If the remainder is zero, then we can safely assume the divisor (x + 7) is a factor of the polynomial f(x)= x^3-3x^2+2x-8.
We use -7 as the divisor in synth. div. This comes from the factor (x + 7):
-7 / 1 3 2 -8
-7 28 -210
-------------------------
1 -4 30 -218
Here, the remainder is -218, not zero, so no, (x+7) is not a factor of f(x)= x^3-3x^2+2x-8.
Answer:
<h3><u>x < 1.975</u></h3>
Explanation:
-12.4x + 8x > -0.4x - 5.2 - 2.7
<em>Add similar elements: -12.4x + 8x = -4.4x</em>
-4.4x > -0.4x - 5.2 - 2.7
<em>Subtract -5.2 - 2.7: -7.9</em>
-4.4x > -0.4x - 7.9
<em>Multiply both sides by 10</em>
-4.4x · 10 > -0.4x - 7.9 · 10
<em>Refine</em>
-44x > -4x - 79
<em>Add 4x to both sides</em>
-44x + 4x > -4x - 79 + 4x
<em>Simplify</em>
-40x > -79
<em>Multiply both sides by -1 (Reverse the inequality)</em>
-40x (-1) > -79 (-1)
<em>Simplify</em>
40x < 79
Divide both sides by 40
40x / 40 < 79 / 40
<em>Simplify</em>
x < ⁷⁹⁄₄₀
<em>Turn the fraction into a decimal</em>
<h3><u>x < 1.975</u></h3>
