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Shkiper50 [21]
3 years ago
9

A pair of tangents to a circle which is inclined to each other at an angle of 60 degree are drawn at ends of two radii. The angl

e between these radii must be :
Mathematics
1 answer:
Sever21 [200]3 years ago
5 0

Answer:

The angle between these radii must be 120º.

Step-by-step explanation:

According to Euclidean Geometry, two tangents to a circle are symmetrical to each other and the axis of symmetry passes through the center of the circle and, hence, each tangent is perpendicular to a respective radius. We represent the statement in the diagram included below.

Then, we calculate the angle of the radius with respect to the axis of symmetry by knowing the fact that sum of internal angles within triangle equals 180º. That is to say:

\theta = 180^{\circ}-90^{\circ}-30^{\circ}

\theta = 60^{\circ}

And the angle between these two radii is twice the result.

\theta' = 2\cdot \theta

\theta' = 120^{\circ}

The angle between these radii must be 120º.

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What is (2n-3p)+4(2n-3)
Klio2033 [76]

Answer:

<h2>10n - 3p - 12</h2>

Step-by-step explanation:

(2n-3p)+4(2n-3)\qquad\text{use the distributive property}\\\\=2n-3p+(4)(2n)+(4)(-3)\\\\=2n-3p+8n-12\qquad\text{combine like terms}\\\\=(2n+8n)-3p-12\\\\=10n-3p-12

7 0
3 years ago
Read 2 more answers
Angelica calculated the distance between the two points shown on the graph below. (1st picture)
Alex Ar [27]
Use the distance formula to find the value of the side lengths.
d=√((x1-x2)²+(y1-y2)²

d of side AC is 6

d of side CB is 10 

Angela's use of the Pythagorean Theorem of 10²+6²+c² is incorrect; she put the right values in the wrong spots, the formula needed is:
6²+10²=c²

Option C- Angelica's side lengths were too long.
7 0
3 years ago
Read 2 more answers
Which of these sets could represent the side lengths of a right triangle?
Jlenok [28]

Answer:

{6, 8, 10} is a set which represents the side length of a right triangle.

Step-by-step explanation:

In a right triangle:

(Base)^{2}  + (Perpendicular)^{2}   = (Hypotenuse)^{2}

Now, in the given triplets:

(a) {4, 8, 12}

Here, (4)^{2}  + (8)^{2}   = 16 + 64  = 80\\\implies H = \sqrt{80}  =  8.94

So, third side of the triangle   8.94 ≠ 12

Hence,  {4, 8, 12} is NOT a triplet.

(b) {6, 8, 10}

Here, (6)^{2}  + (8)^{2}   = 36 + 64  = 100\\\implies H = \sqrt{100}  =  10

So, third side of the triangle  10

Hence,  {6, 8, 10} is  a triplet.

(c) {6, 8, 15}

Here, (6)^{2}  + (8)^{2}   = 36 + 64  = 100\\\implies H = \sqrt{100}  =  10

So, third side of the triangle  10  ≠ 15

Hence,  {6, 8, 15} is  NOT a triplet.

(d) {5, 7, 13}

Here, (5)^{2}  + (7)^{2}   = 25 + 49  = 74\\\implies H = \sqrt{74}  =  8.60

So, third side of the triangle  8.60  ≠ 13

Hence, {5, 7, 13} is  NOT a triplet.

4 0
3 years ago
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