Answer:
.
Step-by-step explanation:
The given function is

Using chain rule differentiate w.r.t. x.
![\left[\because \dfrac{d}{dx}\sin x=\cos x\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Csin%20x%3D%5Ccos%20x%5Cright%5D)
![f'(x)=\cos(9\ln (x))\left[9\dfrac{d}{dx}(\ln (x))\right]](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Ccos%289%5Cln%20%28x%29%29%5Cleft%5B9%5Cdfrac%7Bd%7D%7Bdx%7D%28%5Cln%20%28x%29%29%5Cright%5D)
![\left[\because \dfrac{d}{dx}\ln x=\dfrac{1}{x}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbecause%20%5Cdfrac%7Bd%7D%7Bdx%7D%5Cln%20x%3D%5Cdfrac%7B1%7D%7Bx%7D%5Cright%5D)

Therefore,
.
The 4 curved white corners = 1/4 of whole circle with radius 1/2×6
total white area = 4 [1/4 (pi)(3)^2] = 9pi = 28.27
So the shaded green region (S) = total square - total white area
S = 6×6 - 28.27 = 36 - 28.27 = 7.73 sq. m
Answer:
The answer is 1
Step-by-step explanation:
Any number to the power of 0 is 1
Answer: 
Step-by-step explanation:
By definition, a Dilation is a transformation in which the image has the same shape as the pre-image but size changes.
The center of dilation is a fixed point in the plane, and the scale factor is the ratio of the corresponding sides of the image to the pre-image.
Based on the information provided in the exercise, you know that:

Thererefore, you can determine that the scale factor is:
<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>2</em><em>0</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>