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jeka57 [31]
3 years ago
14

Solve the following question

Mathematics
1 answer:
Kitty [74]3 years ago
5 0

Answer: It's C f"(x)= 15x^2+235 Hope that helps!

Step-by-step explanation:  

Find the Greatest Common Factor (GCF).

GCF = 5

2. Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

5(15x^2/5+235/5)

3. Simplify each term in parentheses and that would give you 5(3x^2+47) and that's why I think it C but i'm not so sure but if you get it right can you please make me Brainliest bye and I hope you get it right!

             

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Answer:

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Step-by-step explanation:

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The expressions which represents the slope of a tangent to the curve y=\frac{1}{x+1} at any point (x, y) are:

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<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}

Given the function:

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When (x + h), we have:

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Next, we would find the derivative of f(x):

f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}

Read more on slope of a tangent here: brainly.com/question/26015157

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It's D I think? I might be wrong, but it cant be A or B because if you plug in 0 as x it doesnt give you the y-intercept of 3 for either. I would wait for another answer just in case though :)
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