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andriy [413]
3 years ago
13

A construction company needs to remove 2 5/6 tons of dirt from a construction site. They can remove 3/10 tons of dirt each hour.

What is the total amount of hours it will take to remove the dirt?
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

Here is a generic way to set up this type of algebra problem.

d = total amount of dirt at the site (tons)

r = rate or removal (tons/hr)

t = time it takes to remove all of the dirt (hr)

d = rt

The total amount of dirt equals the removal rate times hours spent removing all the dirt.

Since you want to solve for t, divide both sides by r

t = d/r

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1.89

Step-by-step explanation:

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Identify the graph of the inequality 2(2x-1)+7<13 or-2x + 5≤-10.
xxMikexx [17]

Answer:

Step-by-step explanation:

2

(

2

x

−

1

)

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<

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Expand LHS

→

4

x

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2

+

7

<

13

4

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(

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This can be represented on the

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graph{2(2x-1)+7<13 [-10, 10, -5, 5]}

5 0
2 years ago
What is the discontinuity and zero of the function f(x) = the quantity of 3 x squared plus x minus 4, all over x minus 1? A. Dis
Firlakuza [10]

Answer:

The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)  

Step-by-step explanation:

\text{The function is given to be : }f(x)=\frac{3x^2+x-4}{x-1}\\\\\implies f(x)=\frac{(3x+4)(x-1)}{(x-1)}

To find the point of discontinuity :

Put the denominator equal to 0

⇒ x - 1 = 0

⇒ x = 1

Also, if the factor (x - 1) gets cancel, then it becomes a hole rather than a asymptote , ⇒ y = 3x + 4 at x = 1

⇒ y = 7

So, Point of discontinuity : (1, 7)

And the zero is : after cancelling the factor (x - 1) put the remaining factor = 0

⇒ 3x + 4 = 0

⇒ 3x = -4

⇒ x = negative four thirds ( zero of the function)

Therefore, The correct option is D. Discontinuity at (1, 7), zero at (negative four thirds, 0)

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3 years ago
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julsineya [31]
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hope this helps you
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