It is the third number line.
b-11=-8
What minus 11 would equal -8? 3!
8+3=11 so it would make sense that the dot would be on 3.
smaller numbers minus larger numbers (such as this equation) always end up being negative, so if you have the answer and at least one of the other numbers, it will be easy to figure out.
In this case you would want to maybe just imagine 11-8=? or go 8+?=11.
11-8=3 and 8+3=11. There you would have your missing number.
We need to compute the diagonal of yhe square.
d²=7²+7²=49×2cm²
d=7×sqrt(2)=7×1.41=9.87cm.
The diagonal we just computed is the diameter of the circle that contains the square.
Since d=9.87 < 11, then indeed, the square fits inside the circle, without touching it.
Do the exponents first. 10 to the -4 is 1/10000 or 0.0001 and 10^ -5 is 0.00001. You end up with (1.7*0.0001)(5*0.00001) which is 0.00017*0.00005 which is 0.0000000085 or 0.085*10^-8
The solution is -5/4= -1 1/4
