The value of x is 1.
The value of y is 4.
Solution:
Given TQRS is a rhombus.
<u>Property of rhombus:
</u>
Diagonals bisect each other.
In diagonal TR
⇒ 3x + 2 = y + 1
⇒ 3x – y = –1 – – – – (1)
In diagonal QS
⇒ x + 3 = y
⇒ x – y = –3 – – – – (2)
Solve (1) and (2) by subtracting
⇒ 3x – y – (x – y) = –1 – (–3)
⇒ 3x – y – x + y = –1 + 3
⇒ 2x = 2
⇒ x = 1
Substitute x = 1 in equation (2), we get
⇒ 1 – y = –3
⇒ –y = –3 – 1
⇒ –y = –4
⇒ y = 4
The value of x is 1.
The value of y is 4.
A 16 karat gold means that there are 16 parts of gold in
24 parts of the gold chain. Therefore the weight of the pure gold is:
pure gold = (16 / 24) * 2.6 ounces
<span>pure gold = 1.73 ounces</span>
8 + 3b= -13
-8. -8
3b= -21
Divide by 3
B= -7
Answer: The information you are given shows that 15% = 30. Multiply 30 by 6 and 2/3 (The number of times 15 goes into 100) and you have your answer. There are 200 people on the beach.
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