Lets say W=Wesley, M=Max, and J=Jared.
So your equations are M=2J, 2M=W, and M+J+W=21days(3 weeks)
So substituting M and W into M+J+W=21 gives you 2J+J+2M=21, substitute M again, to get 2J+J+4J=21 so you get 7J=21 so J= 3 days. Using J=3, substitute in to find M, using M=2J, so M=2(3) so M=6 and using that, substitute into 2M=W, so 2(6)=W so W=12. And 12+6+3=21 to check.
No; you can not have an x-value go to more than one y-value
Question
x+5/x+2 - x+1/x²+2x
Answer:
= (x² - 4x - 1)/[x (x+2)]
= (x² - 4x - 1)/[x² + 2x]
Step-by-step explanation:
x + 5/x + 2 - x + 1/x² + 2x
We factorise the second denominator to give us :
x + 5/x + 2 - x + 1/x(x + 2)
We find the L.C.M of both denominators which is x(x+2).
[x(x + 5)-(x + 1)] / (x (x + 2))
Expand the bracket
=[x² +5x - x -1] / [x (x + 2)]
=(x² - 4x - 1) / [x (x + 2)]
= (x² - 4x - 1)/ [x (x + 2)]
= (x² - 4x - 1) / [x² + 2x]
Answer:
a = 29
b = 64
c = 87
Step-by-step explanation:
Let the angles be a (smallest), b, and c (largest).
We know that a triangle's angles must add up to 180 degrees, so we can construct the following equations.
a + b + c = 180
c = 3a
b = a +35
With some solving and substitution...
a + (a + 35) + c = 180
2a + c = 145
2a + (3a) = 145
5a = 145
a = 29
and therefore,
b = 29 + 35 = 64
c = 3(29) = 87
Answer:
The perimeter of the garden, in meters, is 
Step-by-step explanation:
Diagonal of a square:
The diagonal of a square is found applying the Pythagorean Theorem.
The diagonal of the square is the hypothenuse, while we have two sides.
Diagonal of 12m:
This means that 
, side s. So
Factoring 72:
Factoring 72 into prime factors, we have that:
72|2
36|2
18|2
9|3
3|3
1
So
So, in simplest radical form:
Perimeter of the garden:
The perimeter of a square with side of s units is given by:
In this question, since 
The perimeter of the garden, in meters, is
