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nignag [31]
3 years ago
11

What does x equal to in this problem​

Mathematics
2 answers:
SVEN [57.7K]3 years ago
6 0

------------

20.1

----------

IgorC [24]3 years ago
3 0

Using the triangle, we can find the angle lengths and using those and trig ratios, find the side lengths. Lets say the top side length is "y".

Using the Law of triangles, we can find the missing angle from 180-90-70=20 deg.

Then we can use the Law of sines,

sin(70)/13=sin(20)/y

y=sin(20)*13/sin(70)

y=15.34

Finally, we use the Pythagorean Theorem, (13)^2+(15.34)^2=x^2

x = 20.1

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The quotient of a number and 3 is equivalent to-150
Ksju [112]
I did part of it but the rest idk sorry

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Rewrite the polynomial-9x^5+36x^4+189x^3 in factored form, using the factoring method method you prefer.
ozzi

The polynomial 9x^5+36x^4+189x^3 in factored form is -9 x \times x \times x \times(x-7) \times(x+3)

<u>Solution:</u>

Given, polynomial equation is -9 x^{5}+36 x^{4}+189 x^{3}

We have to find the factored form of the above given polynomial equation.

Let us solve it by grouping.

Now, take the polynomial ⇒ -9 x^{5}+36 x^{4}+189 x^{3}

By taking common term out, we get

\rightarrow-9 x^{3}\left(x^{2}-4 x-21\right)

\rightarrow-9 x^{3}\left(x^{2}-(7-3) x-7 \times 3\right)

Grouping the terms we get,

\rightarrow-9 x^{3}\left(\left(x^{2}-7 x\right)+(3 x-7 x^3)\right)

Taking common terms out from each group,

\rightarrow-9 x^{3}(x(x-7)+3(x-7))

\Rightarrow-9 x^{3}((x-7)(x+3))

\rightarrow-9 x \times x \times x \times(x-7) \times(x+3)

Thus the factored form of polynomial is found out

4 0
3 years ago
A computer generates 80 integers from 1 to 8 at random. The results are recorded in this table.
pishuonlain [190]
I think the answer is 20%
6 0
2 years ago
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A rope is swinging in such a way that the length of the arc traced by a knot at its bottom end is decreasing geometrically. If t
nikdorinn [45]

Answer:

<em>The length of the arc on the sixth swing was </em><em>12.18 ft.</em>

Step-by-step explanation:

A rope is swinging in such a way that the length of the arc traced by a knot at its bottom end is decreasing geometrically.

The third arc is 22 ft. long and the seventh arc is 10 ft.

Hence, the 3rd term is 22 and 7th term is 10.

The length of the arc on the sixth swing is asked, so we have to calculate the 6th term.

We know the nth term in GP is,

T_n=ar^{n-1}

So,

T_3=ar^{3-1}=ar^2  ----------------1

T_7=ar^{7-1}=ar^6  ----------------2

Dividing equation 2 by 1,

\Rightarrow \dfrac{T_7}{T_3}=\dfrac{ar^6}{ar^2}

\Rightarrow \dfrac{10}{22}=\dfrac{ar^6}{ar^2}

\Rightarrow \dfrac{10}{22}=\dfrac{r^6}{r^2}

\Rightarrow \dfrac{r^6}{r^2}=\dfrac{10}{22}

\Rightarrow r^4=\dfrac{10}{22}

\Rightarrow r=\sqrt[4]{\dfrac{10}{22}}

\Rightarrow r=0.8211

Then the 6th term will be,

T_6=ar^{6-1}=ar^5  ----------------3

Dividing equation 2 by 3,

\Rightarrow \dfrac{T_7}{T_6}=\dfrac{ar^6}{ar^5}

\Rightarrow \dfrac{10}{T_6}=\dfrac{a(0.8211)^6}{a(0.8211)^5}

\Rightarrow \dfrac{10}{T_6}=0.8211

\Rightarrow T_6=\dfrac{10}{0.8211}=12.18\ ft

Therefore, the length of the arc on the sixth swing was 12.18 ft.


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If he got 35 right you would do 35+35=70
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2 years ago
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