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There are 50 deer in a particular forest. The population is increasing at a rate of 15% per year. Which exponential growth function represents
the number of deer y in that forest after x months? Round to the nearest thousandth.
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dribeiro
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Answer:
The expression that represents the number of deer in the forest is
y(x) = 50*(1.013)^x
Step-by-step explanation:
Assuming that the number of deer is "y" and the number of months is "x", then after the first month the number of deer is:
y(1) = 50*(1+ 0.15/12) = 50*(1.0125) = 50.625
y(2) = y(1)*(1.0125) = y(0)*(1.0125)² =51.258
y(3) = y(2)*(1.0125) = y(0)*(1.0125)³ = 51.898
This keeps going as the time goes on, so we can model this growth with the equation:
y(x) = 50*(1 - 0.15/12)^(x)
y(x) = 50*(1.013)^x
a^2 - b^2 = (a + b)(a - b)
In this case
49x^4y^2 - 4z^2
= (7x^2y)^2 - (2z)^2
= (7x^2y + 2z)(7x^2y - 2z)
Factors are (7x^2y + 2z) and (7x^2y - 2z)
Answer:
D) 7x^2y + 2z
Answer:
the answer is a because it has no decimal
it is in square root
<u>Step 1</u>
Convert mixed fractions into fractions
6 2/5 = (6*5)+2) / 5 = 32/5
2 2/3 = (2*3)+2) / 3 = 8/3
<u>Step 2</u>
32/5 ÷ 8 / 3 ; where 32/5 is the 1st fraction and 8/3 is the 2nd fraction
<u>Step 2 (A)</u>
Get the reciprocal of the 2nd fraction:
From 8/3 to 3/8
<u>Step 2 (B)</u>
Multiply 1st fraction to the reciprocal of the 2nd fraction
32/5 * 3/8 = (32*3) / (5*8) = 96/40
<u>Step 2 (C)</u>
Simplify the fraction
96/40 divide by 4 will become 24/10
24/10 divide 2 will become 12/5. The simplest fraction of 96/40
The unit rate is 12/5 = 2 2/5 revolutions per second
Factor 36 and add them, make sure both are negatie
1+36=37, nope
2+18=20 nope
3+12=15,nope
4+9=13, nope
6+6=12, nope
the closest one is 20
I hope you meant adds to -20, because if you did, then answer is -2 and -18
if you did mean 36 and adds to -21, then the numbers are
and
, aprox -19.1168 and -1.8831
