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Simora [160]
3 years ago
14

F the angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of th

e tree, what is the height of the tree (to the nearest tenth of a foot)?
A) 14.0 feet
B) 16.9 feet
C) 19.3 feet
D) 20.7 feet
Mathematics
1 answer:
Viktor [21]3 years ago
7 0

<u>Given:</u>

The angle of elevation from the point on the ground to the top of the tree is 34° and the point is 25 feet from the base of the tree.

We need to determine the height of the tree.

<u>Height of the tree:</u>

Let the height of the tree be h.

The height of the tree can be determined using the trigonometric ratio.

Thus, we have;

tan \ \theta=\frac{opp}{adj}

Substituting the values, we get;

tan \ 34^{\circ}=\frac{h}{25}

Multiplying both sides by 25, we have;

tan \ 34^{\circ} \times 25=h

 0.6745 \times 25=h

       16.8625=h

Rounding off to the nearest tenth of a foot, we get;

16.9=h

Thus, the height of the tree is 16.9 feet.

Hence, Option B is the correct answer.

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