Question

What is an equation of the line that passes through the poin (-4,3) and is parallel that line 4x-5y=20

Answer 1

Answer:

y = 4/5x + 6 1/5

Step-by-step explanation:

First, rearrange the equation to put it in the form y = mx + b. Once you put it in that form, m will be the slope and b will be the y-intercept (for example, if the equation is y = 3x - 1 then 3 is the slope and -1 is the y-intercept)

4x - 5y = 20

subtract 4x from both sides

-5y = -4x + 20

divide both sides by -5

y = 4/5 * x - 4

This means the slope of this line is 4/5

Parallel lines always have the same slope, so again you can put your new equation in the form y = mx + b and you have that the slope, or m, = 4/5 so this would be:

y = 4/5x + b

Now, you know that (-4, 3) is a solution so if you plug in x = -4 and y =3 the equation should be true:

3 = 4/5 * -4 + b

3 = -16/5 + b

6 1/5 or 6.2 = b

So the equation is y = 4/5x + 6 1/5 or y = 0.8x + 6.2

Answer 2

Answer:

y = 4/5x + 31/5

Step-by-step explanation:

parallel lines have the same gradient(m)

and the straight like equation is y=mx +c

so to find m , make y the subject.

m will equal to 4/5.

The x and y values are given substitute them and the value to y=mx + c , to find c.

After you have c, place the value of m and c in their places and you'll get: y=4/5x + 31/5