Answer:
f(-3) = g(-3)
Step-by-step explanation:
Let's look at each option to which one is true with regard to the given functions on the graph.
The option that is correct is the option that shows where the graph of f(x) and g(x) intercepts or cut across each other.
Now, take a look at the graph, the line of both functions intercepts at x = -3. At this point, the value of f(-3) and g(-3) is equal to -4.
Therefore: f(-3) = g(-3)
Answer:
120
Step-by-step explanation:
Okay so the equation would be like this
30 + 0.10g = P
g = GB of data used
P = Total Price
Let's work this out now!
So. If his total bill was $42 lets subtract the 30 that comes out every month automatically, now we are just left with 12, if each GB costs 0.10 then all you would do to find out how many GB he used is do 12/0.10 (which is really just 12*10) which will get you 120
Meaning that he used 120 GB
(That's a lot!)
Sum/difference:
Let
This means that
Now, assume that 
is rational. The sum/difference of two rational numbers is still rational (so 5-x is rational), and the division by 3 doesn't change this. So, you have that the square root of 8 equals a rational number, which is false. The mistake must have been supposing that was rational, which proves that the sum/difference of the two given terms was irrational
Multiplication/division:
The logic is actually the same: if we multiply the two terms we get
if again we assume x to be rational, we have
But if x is rational, so is -x/15, and again we come to a contradiction: we have the square root of 8 on one side, which is irrational, and -x/15 on the other, which is rational. So, again, x must have been irrational. You can prove the same claim for the division in a totally similar fashion.
42 less then a number z....
z - 42 <== ur expression
Answer:
Step-by-step explanation:
a. 16b^2c^12-0.25 can be rewritten as follows because it is the difference of two squares:
(4bc^6 - .5)(4bc^6 + .5)
b. 81x^6y^2-0.36a^2
is the difference of two squares, just like (a) (above); its factors are:
(9x^3y - 0.6a)(9x^3y + 0.6a)
