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sp2606 [1]
3 years ago
14

LINEAR EQUATIONS! 7(6-y)=-3(y-2)

Mathematics
1 answer:
BartSMP [9]3 years ago
7 0

Answer:

y=9

Step-by-step explanation:

Isolate the variable by dividing each side by factors that dont contain the variables

move variable to left side and change its sign  

42-7y+3y=6    collect like terms

-7y +3y=6-42

-4y=6-42

-4y=-36     divide both sides of the equation by -4

y=9

hope that helps :)

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<h3>Answer: D) 5</h3>

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Explanation:

If we plugged x = 3 into the expression, then we'd get x-3 = 3-3 = 0 in the denominator. That's not allowed. But we can simplify first

x^2-x-6 factors to (x-3)(x+2). The key here is that (x-3) is a factor. It cancels with the x-3 in the denominator

So, \frac{x^2-x-6}{x-3} = \frac{(x-3)(x+2)}{x-3} = x+2

Allowing us to say,

\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}\frac{(x-3)(x+2)}{x-3}\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = \lim_{x \to 3}(x+2)\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 3+2\\\\\\\displaystyle \lim_{x \to 3}\frac{x^2-x-6}{x-3} = 5\\\\\\

5 0
4 years ago
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