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liberstina [14]
2 years ago
11

Can someone help me ASAP

Mathematics
1 answer:
il63 [147K]2 years ago
5 0
Answer: Option B

Detailed Explanation:

In the figure in Option B, we are given 2 corresponding angles as equal in both triangles. We are also given one corresponding sides as equal.
Therefore, we can prove the congruency by AAS (Angle-Angle-Side).
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Find the area of a slice of a 16 inch pizza that is cut into 8 slices
VARVARA [1.3K]

Answer:

≈ 25 in²

Step-by-step explanation:

The general formula for the area of a circle is:

A=πr²

A = (3.14)(8²)

Since the size of the pizza is 16 inches across, the radius is half of that, or 16÷2 = 8 inches.

A ≈ 201 in²

Since there 8 slices of pizza, you can take the total area and divide by 8:

201 ÷ 8 ≈ 25 in²

6 0
3 years ago
Find the equation of the line which passes through the point (-4,12) and is perpendicular to the given line. Express your answer
Vika [28.1K]

Answer:

y = 1/7x + 88/7

Step-by-step explanation:

y = mx +b

since it is perpendicular you have to get the negative reciprocal of the slope which is 1/7

y = 1/7x + b then you would plug in your points

12 = 1/7(-4) + b and then solve for b

12 = -4/7 + b

+ 4/7

88/7 = b

y = 1/7x + 88/7

8 0
3 years ago
Simplify (-2x3)2 · y · y9.<br><br> A) -4x6y8<br><br> B) -4x4y8<br><br> C) 4x6y10<br><br> D) -4x4y10
Alexxandr [17]

Answer:

Step-by-step explanation:

4 0
3 years ago
Triangle DEF is an isosceles, so AngleDEF Is-congruent-toAngleDFE. A horizontal line has points C, F, E, G. 2 lines extend from
zaharov [31]

Answer:

\angle CFD =105^o

Step-by-step explanation:

Given

\angle D FE = \angle DE F = 75^o

See attachment

Required

Determine the measure of \angle CFD

\angle CFD and \angle DFE are on a straight line.

So:

\angle CFD + \angle DFE = 180^o --- angle on a straight line

Substitute known values

\angle CFD + 75^o = 180^o

Collect like terms

\angle CFD =- 75^o + 180^o

\angle CFD =105^o

5 0
3 years ago
Read 2 more answers
16+ y =24<br> What is the value of y?
andrezito [222]

\rule{300}{1}\\\dashrightarrow\large\blue\textsf{\textbf{\underline{Given question:-}}}

    <em>16+y=24, What is y?</em>

<em />

<em />\dashrightarrow\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}

When solving an equation, we need to make sure that all variables are on one side and all numbers are on the other side.

Since we have numbers on both sides, we need to move all of them to one side:-

\tt{16+y=24}

\tt{y=24-16}

\tt{y=8}

<h3>Good luck with your studies.</h3>

\rule{300}{1}

6 0
2 years ago
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