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2 years ago

Can someone help me ASAP

Mathematics

1 answer:

il63 [147K]2 years ago

5 0

Answer: Option B

Detailed Explanation:

In the figure in Option B, we are given 2 corresponding angles as equal in both triangles. We are also given one corresponding sides as equal.
Therefore, we can prove the congruency by AAS (Angle-Angle-Side).

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Please help!!! Thank you!!!

Bess [88]

Answer:

1. 180° ∑triangle angles=180°

2. 2x

3. 52°

5 0

3 years ago

The equation y = 16 - 2x represents the amount y (in ounces) of trail mix remaining after you eat x servings.

BlackZzzverrR [31]

Answer:

a) x is the independent and y in the dependent

b) y=4

Step-by-step explanation:

b.) How much of the trail mix remains after you eat 6 servings?

Substitute 6 into the x variable.

y=16-2(6)

y=4

5 0

3 years ago

I need help please and thank you

azamat

Answer:

I believe it's B ............

8 0

3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

3 years ago

What is the value of x???

svetoff [14.1K]

I do believe it would be x=30

3 0

3 years ago