Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
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real part of x(y)=4*2-(-9*5)=53 so 1 is x(y): real part of x(y)=
real part of 2x(y)=2*53=106 so 2 is 2x(y)
real part of -x+3y=-4+6=2 so 3 is -x + 3y
real part of 4x-y=16-2=14 so 4 is 4x - y
Answer:
Im taking your points then
<span>35.5/13 = 3.50
there ye go</span>
Answer:
The answer to your question is: V = 92.11 m³
Step-by-step explanation:
Data
π = 3.14
radius sphere = 3 m
radius cylinder = 2 m
height = 5 m
Formula
Volume sphere = 4/3 πr³
Volume cylinder = 1/3 πr²h
Process
Volume sphere = 4/3 (3.14)(3)³
= 113.04 m³
Volume cylinder = 1/3 (3.14)(2)²(5)
= 20.93 m³
Volume of the shaded section = 113.04 - 20.93
= 92.11 m³
