2. A
becasue it say that you randomly ask everyone
<h3>There are 189 bacteria in 5 hours</h3><h3>There are 13382588 bacteria in 1 day</h3><h3>There are
![10(1.8)^{168}](https://tex.z-dn.net/?f=10%281.8%29%5E%7B168%7D)
bacteria in 1 week</h3>
<em><u>Solution:</u></em>
Given that,
A type of bacteria has a very high exponential growth rate of 80% every hour
There are 10 bacteria
<em><u>The increasing function is given as:</u></em>
![y = a(1+r)^t](https://tex.z-dn.net/?f=y%20%3D%20a%281%2Br%29%5Et)
Where,
y is future value
a is initial value
r is growth rate
t is time period
From given,
a = 10
![r = 80 \5 = \frac{80}{100} = 0.8](https://tex.z-dn.net/?f=r%20%3D%2080%20%5C5%20%3D%20%5Cfrac%7B80%7D%7B100%7D%20%3D%200.8)
<em><u>Determine how many will be in 5 hours</u></em>
Substitute t = 5
![y = 10(1 + 0.8)^5\\\\y = 10(1.8)^5\\\\y = 10 \times 18.89568\\\\y \approx 188.96](https://tex.z-dn.net/?f=y%20%3D%2010%281%20%2B%200.8%29%5E5%5C%5C%5C%5Cy%20%3D%2010%281.8%29%5E5%5C%5C%5C%5Cy%20%3D%2010%20%5Ctimes%2018.89568%5C%5C%5C%5Cy%20%5Capprox%20188.96)
y = 189
Thus, there are 189 bacteria in 5 hours
<em><u>Determine how many will be in 1 day ?</u></em>
1 day = 24 hours
Substitute t = 24
![y = 10(1 + 0.8)^{24}\\\\y = 10(1.8)^{24}\\\\y = 10 \times 1338258.84\\\\y = 13382588.45\\\\y \approx 13382588](https://tex.z-dn.net/?f=y%20%3D%2010%281%20%2B%200.8%29%5E%7B24%7D%5C%5C%5C%5Cy%20%3D%2010%281.8%29%5E%7B24%7D%5C%5C%5C%5Cy%20%3D%2010%20%5Ctimes%201338258.84%5C%5C%5C%5Cy%20%3D%2013382588.45%5C%5C%5C%5Cy%20%5Capprox%2013382588)
Thus, there are 13382588 bacteria in 1 day
<em><u>Determine how many will be in 1 week</u></em>
1 week = 168
Substitute t = 168
![y = 10(1 + 0.8)^{168}\\\\y = 10(1.8)^{168}](https://tex.z-dn.net/?f=y%20%3D%2010%281%20%2B%200.8%29%5E%7B168%7D%5C%5C%5C%5Cy%20%3D%2010%281.8%29%5E%7B168%7D)
Thus there are
bacteria in 1 week
Answer:
Option A: 12
Step-by-step explanation:
From the image of the triangle given, we can see that:
XM = ZM
We are given that:
XM = 2x + 2 and ZM = 4x - 8
Thus;
2x + 2 = 4x - 8
Rearrange to get;
4x - 2x = 8 + 2
2x = 10
x = 10/2
x = 5
Thus, XM = 2(5) + 2
XM = 12