Answer:
The equation of the line that passes through the point (2, -1) and has a slope of -3 will be:
Step-by-step explanation:
The slope-intercept form of the line equation
y = mx+b
where
Given
substituting m = -3 and the point (2, -1) in the slope-intercept form of the line equation
y = mx+b
-1 = -3(2)+b
-1 = -6 + b
b = -1 + 6
b = 5
Thus, the y-intercept form of the line equation is b = 5
now substituting b = 5 and m = -3 in the slope-intercept form of the line equation
y = mx+b
y = -3x + 5
Thus, the equation of the line that passes through the point (2, -1) and has a slope of -3 will be:
