Which data set has a wider spread? Why? Set A: {9, 11, 24, 11, 4, 20, 16, 7, 18, 15, 28, 6} Set B: {9, 12, 15, 3, 21, 24, 5, 9,
olchik [2.2K]
Data Set A:
Lowest Value is 4
Highest Value is 28
Range = 28 - 4 = 24
Data Set B:
Lowest Value is 3
Highest Value is 24
Range = 24 - 3 = 21
Data Set A has bigger range than Data Set B, hence it has a wider range
Answer: Set A has a wider spread because its range is greater.
Answer:
Step-by-step explanation:
Asked: How many square tables are needed to place 100 pupils?
Given: Square table each has 4 pupils to sit
operation : Multiplication, subtraction, Division
Solve:
Number of pupils in 9 rectangular tables = 9*8 = 72 pupils
Remaining pupils = 100 - 72 = 28
Number of square table needed =28 ÷ 4 = 7
7 square tables are needed.
Answer:
y = 3x-2
Step-by-step explanation:
We can find the slope using the equation for slope
m = (y2-y1)/(x2-x1)
= (13-4)/(5-2)
= 9/3
= 3
We know the slope and a point, so we can use point slope form to make an equation
y-y1 = m(x-x1)
y-4 = 3(x-2)
Distribute
y-4 = 3x-6
Add 4 to each side
y-4+4 = 3x-6+4
y = 3x-2
This is in slope intercept form (y= mx+b)
Answer:
Acute Triangle
Step-by-step explanation:
<u><em>Angles in a triangle add up to 180 degrees.</em></u>
So,
x+2x+2x = 180
=> 5x = 180
Dividing both sides by 5
=> x = 36
<u><em>So, The lengths are:</em></u>
=> 36
=> 72
=> 72
<em><u>Since all the angles are less than 90 degrees, It is an acute triangle.</u></em>
<u>Solution-</u>
As given in △ABC,
As from the properties of trigonometry we know that, the greater the angle is, the greater is the value of its sine. i.e
According to the sine law,
In order to make the ratio same, even though m∠A>m∠B>m∠C, a must be greater than b and b must be greater than c.
Also given that its perimeter is 30. Now we have to find out whose side length is 7. So we have 3 cases.
Case-1. Length of a is 7
As a must be the greatest, so b and c must be less than 7. Which leads to a condition where its perimeter won't be 30. As no 3 numbers less than 7 can add up to 30.
Case-2. Length of b is 7
As b is greater than c, so c must 6 or less than 6. But in this case the formation of triangle is impossible. Because the triangle inequality theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side. If b is 7 and c is 6, then a must be 17. So no 2 numbers below 7 can add up to 17.
Case-3. Length of c is 7
As this is the last case, this must be true.
Therefore, by taking the aid of process of elimination, we can deduce that side c may have length 7.
