In the "magic square" at the right, the four numbers

What are the domain and range of f(x) = |x + 6|?

san4es73 [151]

9514 1404 393

Answer:

domain: all real numbers
range: y ≥ 0

Step-by-step explanation:

The function is defined for all values of x, so its domain is all real numbers.

The function can produce values of f(x) that are 0 or greater, so its range is ...

y ≥ 0

4 0

2 years ago

Give two systems of equations that would be easier to solve by substitution than by elimination. Then give two systems that woul

Daniel [21]

These techniques for elimination are preferred for 3rd order systems and higher. They use "Row-Reduction" techniques/pivoting and many subtle math tricks to reduce a matrix to either a solvable form or perhaps provide an inverse of a matrix (A-1)of linear equation AX=b. Solving systems of linear equations (n>2) by elimination is a topic unto itself and is the preferred method. As the system of equations increases, the "condition" of a matrix becomes extremely important. Some of this may sound completely alien to you. Don't worry about these topics until Linear Algebra when systems of linear equations (Rank 'n') become larger than 2.

5 0

2 years ago

Clinton decided to by 300 shares of stock in a electronics company.Each share costs $60.Which of the following could he use to f

REY [17]

$60.00×300=18,000 ..............

3 0

3 years ago

20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

IRINA_888 [86]

<u>ANSWER: </u>

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

<u>SOLUTION: </u>

Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

5 0

3 years ago

Please someone tell me the answers to these I dont remember how to do it

Delvig [45]

Answer:

1) (3 - 6x)(-8) = (-8)(3) - (-8)(6x) = -24 - (-48x) = -24 + 48x = 48x - 24

2) (-12)(2x - 3) = (-12)(2x) - (-12)(3) = -24x - (-36) = -24x + 36 = 36 - 24x

3) (10 - 2x)9 = (9)(10) - (9)(2x) = 90 - 18x

4) (-5)(11x - 2) = (-5)(11x) - (-5)(2) = -55x - (-10) = -55x + 10 = 10 - 55x

5) (1 - 9x)(-10) = (-10)(1) - (-10)(9x) = -10 - (-90x) = -10 + 90x = 90x - 10

6) (-6)(x + 8) = (-6)(x) + (-6)(8) = -6x + (-48) = -6x - 48

7) (-4 + 3x)(-8) = (-8)(-4) + (-8)(3x) = 32 + (-24x) = 32 - 24x

8) (-5)(1 - 11x) = (-5)(1) - (-5)(11x) = -5 - (-55x) = -5 + 55x = 55x -5

9) (-12x + 14)(-5) = (-5)(-12x) + (-5)(14) = 60x + (-70) = 60x - 70

Step-by-step explanation:

The distributive property is a(b + c) = ab + ac

8 0

2 years ago