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velikii [3]
3 years ago
5

Does the point (-4, 2) lie inside or outside or on the circle x^2 + y^2 = 25?​​

Mathematics
2 answers:
galben [10]3 years ago
6 0

Given equation of the Circle is ,

\sf\implies x^2 + y^2 = 25

And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,

\sf\implies (x-0)^2 +( y-0)^2 = 5 ^2

Here we can say that ,

• Radius = 5 units

• Centre = (0,0)

Finding distance between the two points :-

\sf\implies Distance = \sqrt{ (0+4)^2+(2-0)^2} \\\\\sf\implies Distance = \sqrt{ 16 + 4 } \\\\\sf\implies Distance =\sqrt{20}\\\\\sf\implies\red{ Distance = 4.47 }

Here we can see that the distance of point from centre is less than the radius.

Hence the point lies within the circle.

bekas [8.4K]3 years ago
3 0

Answer:

Inside

Step-by-step explanation:

Check the picture below

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HELP. DONT ANSWER IF NOT 100% SURE. WILL GIVE BRANILEIST ASAP!
ehidna [41]

Answer:

B.

{ \tt{f(x) =  \sqrt[3]{x + 11} }}

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{ \tt{m =  \sqrt[3]{x + 11} }} \\ { \tt{ {m}^{3}  = x + 11}} \\ { \tt{ {m}^{3}  - 11 = x}} \\ { \tt{ {f}^{ - 1}(x) =  {m}^{3}  - 11 }}

substitute for x in place of m:

{ \bf{f {}^{ - 1}(x) =  {x}^{3} - 11  }}

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