Answer:
66 inches ;
95.44 ;
4
Step-by-step explanation:
Given that:
Normal distribution with;
Mean(m) = 66 inches
Standard deviation (s) = 3 inches
A.) If a horse is chosen at random, Expected height will be equal to the mean of the distribution = 66 inches
B.) percentage horses who are between 60 and 72 inches
Zscore = ( x - m) / s
x = 60
Zscore = (60 - 66) / 3
Zscore = - 6/3
= - 2
P(Z < - 2) = 0.0228
Zscore = ( x - m) / s
x = 72
Zscore = (72 - 66) / 3
Zscore = 6/3
= 2
P(Z < 2). = 0.9772
Between 60 and 72
0.9772 - 0.0228 = 95.44
c) In a particular year there are 25 horses running in the Melbourne Derby. How many of these would you expect to have a height of less than 63 inches?
Zscore = ( x - m) / s
x = 63
Zscore = (63 - 66) / 3
Zscore = - 3/3
= - 1
P(Z < - 1) = 0.1587
0.1587 * 25 = 3. 967 = 4
Answer:
$11 per day
Step-by-step explanation:
44÷4=11
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