What are the x and y-intercepts of the line described by the equation?

1. A group of three digits seperated by commas in a multidigit number is a _____________.

Ivanshal [37]

Period, exponent and 80 because 800 divided by 10 is 80...

8 0

3 years ago

What is the domain and range of (2)/(x^2-2x-3)?

givi [52]

Domain: All real numbers or (-infinity, infinity)

Range: [-8, infinity)

4 0

3 years ago

chef ollie has a community garden.she uses 2/6 of the farmland to grow beets and 1/6 of the farmland to grow kale. how much of t

Lorico [155]

Answer:

1/2 of farm land left.

Step-by-step explanation:

Ok so we know that Chef Ollie has a community garden. And that she uses $\frac{2}{6}$ of the farmland to grow beets. The denominator 6 lets you know immediately that the land is divided into equal 6 pieces. We also know that Chef Ollie uses another $\frac{1}{6}$ of the farmland to grow kale.

Because the we need to find out how much land Chef Ollie has left, we need to subtract the amount she used from the whole. Before we can do that we must add up the total amount of used land, and since the denominators are the same we can directly add and subtract with having to change the denominator.

Step 1: Write down important numbers.

$\frac{2}{6}$ , $\frac{1}{6}$ ,

Step 2: Add those numbers together.

$\frac{2}{6} + \frac{1}{6} = \frac{3}{6}$ or $\frac{1}{2}$

Step 3: Write an expression/equation.

$\frac{6}{6} - \frac{3}{6} \\or\\1 - \frac{1}{2}$

Step 4: Solve

= $\frac{3}{6}\\or\\\frac{1}{2}$

(can be written both ways)

And you get your answer: After Chef Ollie has used $\frac{2}{6}$ to grow beets and $\frac{1}{6}$ to grow kale, she has $\frac{1}{2}$ of her farmland left untouched.

To represent this you could draw a circle divided in 6 pieces and shade 3 of them, or simply draw a circle and shade half. As well as drawing a rectangle and dividing it into 6 pieces, shading 3, or draw a rectangle, and shade half.

You are welcome ;) .

3 0

3 years ago

Given the following information about a hypothesis test of the difference between two means based on independent random samples,

HACTEHA [7]

Answer:

$S^2_p =\frac{(13-1)(5)^2 +(10 -1)(3)^2}{13 +10 -2}=18.143$

And the deviation would be just the square root of the variance:

$S_p=4.259$

Then the statistic is given by:

$t=\frac{(12 -9)-(0)}{4.259\sqrt{\frac{1}{13}+\frac{1}{10}}}=1.674$

And the correct option would be:

t = 1.674

Step-by-step explanation:

Data given:

$n_1 =13$ represent the sample size for group 1

$n_2 =10$ represent the sample size for group 2

$\bar X_1 =12$ represent the sample mean for the group 1

$\bar X_2 =9$ represent the sample mean for the group 2

$s_1=5$ represent the sample standard deviation for group 1

$s_2=3$ represent the sample standard deviation for group 2

We are assuming two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

And the statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

The system of hypothesis on this case are:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The pooled variance is given by:

$S^2_p =\frac{(13-1)(5)^2 +(10 -1)(3)^2}{13 +10 -2}=18.143$

And the deviation would be just the square root of the variance:

$S_p=4.259$

Then the statistic is given by:

$t=\frac{(12 -9)-(0)}{4.259\sqrt{\frac{1}{13}+\frac{1}{10}}}=1.674$

And the correct option would be:

t = 1.674

4 0

3 years ago

Select all of the following expressions that are equivalent to 16a+40 .

lina2011 [118]

The first one is true
4(4a+10) is
16 a + 40 after distribution

The second one is also true
2(8a+20)
16a + 40 after distribution

Third is not true
4a(4+10a)
16a + 40a^2 after distribution

Last one is also true
8(2a+5)
16a + 40 after distribution

Hope this helps :)

5 0

3 years ago