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3 years ago

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Mathematics

1 answer:

kipiarov [429]3 years ago

3 0

B. IT tools expedite different business take

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Help please Can you clear fractions in an equation by multiplying each side by a common denominator other than the LCD? Give an

Katena32 [7]

Yes here is an example:_

x/4 + 5/6 = 2

The LCD of 4 and 6 is 12 but we can also multiply through by 24 to clear the fractions:-

x/4 * 24 + 5/6 * 24 = 2 + 24

6x + 20 = 40

This will give us the same result if we multiplied through by 12.

7 0

2 years ago

Are is 16/14 and 64/60

zalisa [80]

Do you know how to solve this??

6 0

3 years ago

(1 point) consider the function f(t)=⎧⎩⎨⎪⎪⎪⎪0,−5,−6,6,t<00≤t<11≤t<7t≥7;f(t)={0,t<0−5,0≤t<1−6,1≤t<76,t≥7; 1. wr

sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
$f(t)\equiv-5u(t)-u(t-1)+12u(t-7)$

5 0

3 years ago

I need help please?!!!!!!

Alika [10]

Answer: The is B

Step-by-step explanation:

4 0

3 years ago

25 - X= pls anwer this

OlgaM077 [116]

Answer:

x = 25

Step-by-step explanation:

hope this helps

5 0

2 years ago

Read 2 more answers