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butalik [34]
3 years ago
7

What the surface area of the cube​

Mathematics
1 answer:
kari74 [83]3 years ago
3 0

Answer:

sum of area of All six faces of cube is it's total surface area

Step-by-step explanation:

surface area of a cube =6*area of faces =6*(side) square

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A delivery truck is transporting boxes of two size: the combined weight of a large box and a small box is 65 pounds. The truck i
Bas_tet [7]

pretty much about the same as before.

a = weight of a large box

b = weight of a small box.

we know their combined weight is 65 lbs, thus a + b = 65.

we also know that the truck has 60 large ones, and 55 small ones, thus 60*a is the total weight for the large ones and 55*b is the total weight for the small ones, and we know that is a total of 3775, 60a + 55b = 3775.

\bf \begin{cases} a+b=65\\ \boxed{b}=65-a\\ \cline{1-1} 60a+55b=3775 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{60a+55\left( \boxed{65-a} \right)=3775} \\\\\\ 60a+3575-55a=3775\implies 5a+3575=3775\implies 5a=200 \\\\\\ a=\cfrac{200}{5}\implies \blacktriangleright a = 40 \blacktriangleleft \\\\\\ \stackrel{\textit{since we know that}}{b=65-a\implies }b=65-40\implies \blacktriangleright b=25\blacktriangleleft

6 0
4 years ago
if 1/2 an apple was shared equally among 3 people. what fracton of the who apple did each person recive.
enyata [817]

Answer:

1/6

Step-by-step explanation:

1/2/3 is a sixth of an apple that all 3 people equally shared.

3 0
4 years ago
A path for a new city park will connect the park entrance to Main Street, as shown to the right. The path
sweet-ann [11.9K]

Main street is vertical to park entrance

5 0
3 years ago
PLEASE HELP!!!!!!!!!!
Oksanka [162]

Answer:

B

Step-by-step explanation:

Data set D does not contain the value 128, which is the median value.

Data set C does not contain the outlier value 91.

Data set A contains value 168, which does not show up on the plot.

The only remaining choice is B.

_____

In order, the data values of set B are ...

... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152

The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)

6 0
4 years ago
Read 2 more answers
Factorise 24e^2-28e-12
Helga [31]

Answer:

4(2e - 3)(3e + 1)

Step-by-step explanation:

Given

24e² - 28e - 12 ← factor out 4 from each term

= 4(6e² - 7e - 3) ← factor the quadratic

Consider the factors of the product of the e² term and the constant term which sum to give the coefficient of the e- term.

product = 6 × - 3 = - 18 and sum = - 7

The factors are - 9 and + 2

Use these factors to split the e- term

6e² - 9e + 2e - 3 ( factor the first/second and third/fourth terms )

= 3e(2e - 3) + 1 (2e - 3) ← factor out (2e - 3) from each term

= (2e - 3)(3e + 1)

Then

24e² - 28e - 12 = 4(2e - 3)(3e + 1) ← in factored form

8 0
3 years ago
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