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2 years ago

What is the surface area of this cone?

Mathematics

1 answer:

DanielleElmas [232]2 years ago

8 0

surface area of this cone?

Use A= 3.14 and round your answer to the nearest hundredth

9 ft

6 ft

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Jacob wants to use an elevator to carry identical packages having the same weight. Each package weighs 3 pounds and Jacob weighs

zimovet [89]

Answer:

Your answer is B

Step-by-step explanation:

Take 300 and subtract it by 99 you'll get 201

3 times 67 is 201

Which is why your answer is B!

Hope this helps! -Queenb369

(P.S, If you could give me the brainlist if i'm right, that will be great thanks!)

6 0

3 years ago

Read 2 more answers

Evaluate the expression 42+6⋅52−33÷32

mote1985 [20]

The first step to solve this is to multiply the numbers
42 + 312 - 33 ÷ 32
then divide the numbers
42 + 312 - 1.03125
use the addition and subtraction rules to calculate the expression
352.96875
this means that the correct answer to your question will be 352.96875.
let me know if you have any further questions
:)

7 0

3 years ago

A rectangular field is two times as long as it is wide. If the perimeter of the field is 450 feet, what are the dimensions of th

lys-0071 [83]

Hi There,

----------------------------------------

We Know:

Total Perimeter = 450 feet

Length is 2 times the width.

----------------------------------------

Solution:

Length = 150

Width = 75

75 x 2 = 150

150 + 150 + 75 + 75 = 450

----------------------------------------

Answer:

Length = 150 feet.

Width = 75 feet.

----------------------------------------

Hope This Helps :)

5 0

3 years ago

Use the graph of △ABC with midsegments DE, EF and DF. Show that EF is parallel to AC and that EF=1/2 AC

Vinvika [58]

According to the midsegment theorem, the midsegments are parallel to

and half the length of the opposite side.

The completed statement are as follows;

Because the slopes of $\overline{EF}$ and $\overline{AC}$ are both -4, $\overline{EF}$ ║ $\overline{AC}$

EF = $\underline{\sqrt{17}}$ and AC = $\underline{2 \cdot \sqrt{17} }$

Because $\underline{\sqrt{17} }$ = $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17} }$ , $EF = \frac{1}{2} \cdot AC$

Reasons:

From the given graph of ΔABC, we have;

Coordinates of the points A, B, and C are; A(-5, 2), B(1, -2), and C(-3, -6)

The coordinates of the point D and E on $\mathbf{\overline{DE}}$ are; D(-4, -2), and E(-2, 0)

The coordinates of the point F is; F(-1, -4)

$Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\displaystyle Slope \ of \ line \ \overline{AC} = \mathbf{\frac{(-6) - 2}{-3 - (-5)} = \frac{-8}{2}} = -4$

$\displaystyle Slope \ of \ line \ \overline{EF} = \frac{0 - (-4)}{-2 - (-1)} = \frac{4}{-1} = -4$

$Length \ of \ segment,\ l = \sqrt{\left (x_{2}-x_{1} \right )^{2}+\left (y_{2}-y_{1} \right )^{2}}$

Length of EF = √((-1 - (-2))² + (-4 - 0)²) = √(17)

Length of AC = √((-3 - (-5))² + (-6 - 2)²) = √(4 × 17) = 2·√(17)

Therefore, we have;

Because the slope of $\mathbf{\overline {EF}}$ and $\mathbf{\overline {AC}}$ are both , -4, $\overline {EF}$ ║ $\overline {AC}$ . EF = $\underline{\sqrt{17}}$ , and AC

= $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}$ ,. Because $\underline{\sqrt{17}}$ = $\underline{\frac{1}{2} \cdot 2 \cdot \sqrt{17}}$ , $EF =\mathbf{ \frac{1}{2} AC}$

Learn more about midsegment theorem of a triangle here:

brainly.com/question/7423948

8 0

2 years ago

Please answer asap (look at picture) please answer both

exis [7]

0,2 is the answer since that’s where both lines intersect

3 0

3 years ago