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Elena L [17]
3 years ago
5

Find a real number between -√9 and √25. a.-4 b.1 c.-5 d.6

Mathematics
2 answers:
Alex3 years ago
6 0

Answer:

b) 1

Step-by-step explanation:

1 * 1 = 1

And 1 is a real number.

If my answer helped, kindly mark me as th ebrainliest!!

Thank You!!

Aleonysh [2.5K]3 years ago
3 0

Answer:

-5 is the answer

Step-by-step explanation:

c is the answer

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spayn [35]
4x^2-3x+4y^2+4z^2=0
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3 years ago
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Answer: here it is!

Step-by-step explanation :

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7 0
2 years ago
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The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
Find the quotient -60, 10​
Bond [772]

Answer:

-6

When dividing a negative number by a positive number, your answer will result in a negative number.

6 0
4 years ago
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John goes to a bookstore. he wants to buy at. most 25 books and spend at most $75. paperback books cost 1.75 and har cover books
Yanka [14]

Answer:

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Step-by-step explanation:

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