The complete question in the attached figure
Part A) How much sand is currently in the container?
[sand currently in the container]=(5)*(4 1/2)*(2.25)-----> (5)*(4.5)*(2.25)
[sand currently in the container]=50.625 in³
the answer Part a) is 50.625 in³Part B) How much more sand could the container hold before?
[sand could the container hold before]=[5*4.5*3]-[50.625]
[sand could the container hold before]=[67.5]-[50.625]------> 16.875 in³
the answer Part B) is 16.875 in³
Part C) What percent of the container is filled with sand?
the volume of container is [5*4.5*3]=67.5 in³
the volume filled with sand=50.625 in³
therefore
if 100%----------------> 67.5 in³
X---------------------> 50.625 in³
X=(50.625*100)/67.5=75 %
the answer Part C) is 75%
To solve this, you need to plug in the numbers for <em>h</em>.
-4(-12) ≥ 8 48 ≥ 8 yes
-4(-7) ≥ 8 28 ≥ 8 yes
-4(-5) ≥ 8 20 ≥ 8 yes
-4(-3) ≥ 8 12 ≥ 8 yes
-4(-2) ≥ 8 8 ≥ 8 yes
-4(-1) ≥ 8 4 ≥ 8 no
-4(1) ≥ 8 -4 ≥ 8 no
-4(3) ≥ 8 -12 ≥ 8 no
-4(8) ≥ 8 -32 ≥ 8 no
Hope this helped!
Answer:
Given functions,


Since, by the compositions of functions,
1. (g◦f)(x) = g(f(x))


Since, (g◦f) is defined,
If 3 - x² ≥ 0
⇒ 3 ≥ x²
⇒ -√3 ≤ x ≤ √3
Thus, Domain = [-√3, √3]
2. (f◦g)(x) = f(g(x))


Since, (g◦f) is defined,
If x ≥ 0
Thus, Domain = [0, ∞)
3. (f◦f)(x) = f(f(x))




Since, (f◦f) is a polynomial,
We know that,
A polynomial is defined for all real value of x,
Thus, Domain = (-∞, ∞)
Answer:
9.230095943 or 9.2
Step-by-step explanation:
Trigonometry: sine, cosine, tang: Sohcahtoa
O: opposite(side from angle)
H: hypotenuse(side opposite from 90*)
A: Adgacent(side from angle)
Use scientific calculator: tang(40*) x 11 = 9.230095943