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3 years ago

Solve the following equation when x = 8 15x - 2 =

Mathematics

2 answers:

NemiM [27]3 years ago

6 0

Answer:

118

Step-by-step explanation:

15(8)-2

120-2

118

Brainly plss?

erastovalidia [21]3 years ago

3 0

Answer:

118

Step-by-step explanation:

you do 15 x 8 then subtract 2 from the product

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Simplify 4n5 + 3.5n5 + (-2.1n5). 4.4 n5 5.4 n5 20 n5 6.4 n5

ella [17]

Answer:

$4 {n}^{5} + 3.5 {n}^{5} + ( - 2.1 {n}^{5} )$

first create a bracket:

$= ( {4n}^{5} + 3.5 {n}^{5} ) + ( - 2.1 {n}^{5} )$

then solve the first bracket:

$= {7.5 {n}^{5} } + ( - 2.1 {n}^{5} )$

then open the remaining bracket:

$= {7.5n}^{5} - {2.1n}^{5}$

carryout the subtraction operation:

$= (7.5 - 2.1) {n}^{5} \\ { \boxed{ = {5.4n}^{5} }}$

7 0

3 years ago

Solve for the two possible values of X:

lbvjy [14]

X1 = 1.71429
X2 = 3.4

7 0

3 years ago

Farmer Joe is planning to fence in a garden area in a portion of his field which is 75 feet wide. The farmer would like to creat

LenKa [72]

He could make his plot 300 feet long

5 0

3 years ago

2 numbers total 47 and have a difference of 21 what are the two numbers

murzikaleks [220]

x+y = 47

x-y = 21

------------ add together

2x =68 divide by 2

x=34

x+y = 47

34+ y = 47

subtract 34 from each side

y = 13

the two numbers are 34 and 13

7 0

3 years ago

H(t)= (t+3)^2 + 5

oee [108]

Answer:

The average rate of change for the given function in the interval (-5, -1) is 0 (zero)

Step-by-step explanation:

The average rate of change of a function over an interval is the quotient between the difference between the function evaluated at the ends of the interval divided by the length of the interval. That is for our case:

the average rte of change of h(t) in the interval (-5, -1) is:

$\frac{h(-1)-h(-5)}{-1+5}$

so we find:

$h(-1)=(-1+3)^2+5=2^2+5=4+5=9\\and\\h(-5)=(-5+3)^2+5=(-2)^2+5=4+5=9$

then the average rate of change becomes:

$\frac{h(-1)-h(-5)}{-1+5}=\frac{9-9}{4} =\frac{0}{4} =0$

5 0

3 years ago