When a quadratic equation ax^2+bx+c has a double root, the discriminant,
D=b^2-4ac=0
Here
a=2,
b=b,
c=18
and
D=b^2-4ac=b^2-4*2*18=0
solve for b
b^2-144=0
=> b= ± sqrt(144)= ± 12
So in order that the given equation has double roots, the possible values of b are ± 12.
Answer:
I think it’s 28.3
Step-by-step explanation:
Sorry If I’m wrong
Answer : C
we need to the value of f(–1)
Table is given in the question
From the table ,
f(x) = 4 when x= -5, that is f(-5) = 4
f(x) = 0 when x= -1, that is f(-1) =0
f(x)= -1 when x=6, that is f(6) = -1
f(x)= -3 when x=9, that is f(9) = -3
So, the value of f(–1) = 0
Answer: ∠p and ∠s, ∠q and ∠r
Step-by-step explanation:
From the lines on the angles indicate which ones are corresponding, for example angles p and s both have 2 lines, while angles q and r both have one line.
