Answer:
ΔV = 0.36π in³
Step-by-step explanation:
Given that:
The radius of a sphere = 3.0
If the measurement is correct within 0.01 inches
i.e the change in the radius Δr = 0.01
The objective is to use differentials to estimate the error in the volume of sphere.
We all know that the volume of a sphere

The differential of V with respect to r is:

dV = 4 πr² dr
which can be re-written as:
ΔV = 4 πr² Δr
ΔV = 4 × π × (3)² × 0.01
ΔV = 0.36π in³
5.4 because the 9 bumps it to 5.35.
And the 5 bumps it to 5.4.
Answer:
49 students/7 teams= 7 students per team
49/7=7
i hope this work for you
and sory if im wrang
Hi,
The answer is D, (y = 8x)
Hope this helps.
r3t40
Answer:
≈67.81
Step-by-step explanation: