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Monica [59]
2 years ago
8

Find the length of U and V. Show work. Giving out brainliest answer.

Mathematics
1 answer:
MrRissso [65]2 years ago
3 0

Answer:

u =√6

v =√5

Step-by-step explanation:

u = √(1²+2²+1²) =√(1+4+1) = √6

v = √(1²+2²) =√(1+4) = √5

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Is x=4 and y=5 perpendicular
faltersainse [42]

True!

<h2>Explanation:</h2>

The Cartesian coordinate system is formed by two perpendicular axes, which are the x-axis and y-axis. In this problem, we are given two lines:

x=4 \ and \ y=5

  • The line x=4 is parallel to the y-axis and has an undefined slope.
  • The line y=5 is parallel to the x-axis and has a slope of zero.

Since the x and y-axes are perpendicular, then the lines x=4 \ and \ y=5 are also perpendicular.

<h2>Learn more:</h2>

Cartesian coordinate system: brainly.com/question/2141683

#LearnWithBrainly

6 0
3 years ago
A 4m ladder rest against a vertical wall with its foot 2m from the wall.How far up the wall does the ladder reach?
adell [148]

A) How high up the wall does it reach?

Use the Pythagorean theorem

Height^2 + Base^2 = Hyp^2

H^2+ 2^2 = 4^2         Subtract the 2^2 from both sides

H^2 = 4^2 -2^2          Multiply the square roots of both the numbers

H^2= 16 - 4

H^2 = 12

H= sqrt(12) m

Hope this helps

4 0
3 years ago
I am a 2nd grader i need to know 120/1234x1234x70x0x90x100x12x13x34
maxonik [38]
Anything multiplied by 0 =0
So what is left is 90x100x12x13x34 which is=47,736,000
7 0
3 years ago
X^2+43xy+590y^2 resolve into factors​
Natalija [7]

Step-by-step explanation:

We have:

x - y = 43 , xy = 15

To find, the value of x^2+y^2x

2

+y

2

= ?

∴ x - y = 43

Squaring both sides, we get

(x - y)^2(x−y)

2

= 43^243

2

⇒ x^2+y^2x

2

+y

2

- 2xy = 1849

Using the algebraic identity,

(a - b)^2(a−b)

2

= a^2+b^2a

2

+b

2

- 2ab

⇒ x^2+y^2x

2

+y

2

= 1849 + 2xy

Put xy = 15, we get

x^2+y^2x

2

+y

2

= 1849 + 2(15)

⇒ x^2+y^2x

2

+y

2

= 1849 + 30

⇒ x^2+y^2x

2

+y

2

= 1879

∴ x^2+y^2x

2

+y

2

= 1879

I will send hint follow this hint then slove it .

thankyou

7 0
3 years ago
In each of problems 5 through 11, find the general solution of the given differential equation
Brrunno [24]

The complete question is

"Find the general solution of the given differential equation

y''-y=0, y1(t)=e^t , y2(t)=cosht

The function y(t)=e^t  is the solution of the given differential equation.

The function y(t)=cosht is the solution of given differential equation.

<h3>What is a function?</h3>

The function is a type of relation, or rule, that maps one input to specific single output.

Given;

y_1(t) = e^t

Given differential equations are,

y''-y = 0

 So that,  

y' (t) = e^t, y'' (t) = e^t

Substitute values in the given differential equation.

e^t -e^t=0

                   

Therefore, the function y(t)=e^t  is the solution of the given differential equation.

Another function;

y(t)=cosht  

So that,  

y"(t)=sinht\\\\y"(t)=cosht

Hence, function y(t)=cosht is solution of given differential equation.

Learn more about function here:

brainly.com/question/2253924

#SPJ1

7 0
2 years ago
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