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Fofino [41]
3 years ago
10

What is the equation of y = x3 with the given transformations? horizontal translation right 10 units and vertical translation do

wn 12 units
A. y = (x - 10)3 - 12
B. y = (x + 10)3 - 12
C. y = (x - 12)3 + 10
D. y = (x + 12)3 + 10
Mathematics
2 answers:
Nimfa-mama [501]3 years ago
6 0

this is 100% the answer

y = (x - 10)3 - 12

Nookie1986 [14]3 years ago
5 0
A. y = (X - 10)^3 - 12
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Find the discriminant of the following quadratic equation then state the number of rational, irrational, and imaginary solutions
lianna [129]

Answer:

  • -6x² - 6 = -7x - 9
  • -6x² + 7x - 6 + 9 = 0
  • -6x² + 7x + 3 = 0
  • 6x² - 7x - 3 = 0

<u>Discriminant:</u>

  • D = (-7)² - 4*6*(-3) = 49 + 72 = 121

<u>Since D > 0, there are 2 real solutions:</u>

  • x = (- (-7) ±√121 )/12
  • x = (7 ± 11)/12
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3 years ago
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PLZZ HELP!!!! ASAP PLZ!!!!<br> XTRA POINTS!!!
schepotkina [342]

Answer:

38.1 cm²

Step-by-step explanation:

area of full circle = π6² = 113.04 cm²

area of 150° segment = (150/360)(113.04) = 47.1 cm²

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triangle height = cos 75° x 6 = 1.553

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3 0
3 years ago
Find the difference: (6y3 + 17y − 3) − (4y3 − 11y + 9)
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</span>= 6y3 + 17y − 3 − 4y3 + 11y - 9
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3 years ago
Change 2 hours and 36 mins to a mixed number
defon
You know you have two hours which will be the whole number. Then you take 36min and put it over 60min (total number of min in an hour) and you simplify by 6 to get 6/10 which can be simplified again to 3/5 so your final mixed number is
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TO TRANSMIT INFORMATION ON THE INTERNET, LARGE FILES ARE BROKEN INTO PACKETS OF SMALLER SIZES. EACH PACKET HAS 1,500 BYTES OF IN
stich3 [128]

Answer:

<u>A.</u> <u>It would be needed 20 packets to transmit 30,000 bytes of information and B. 45'000,000 (45 million) of bytes could be transmitted in 30,000 packets.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the question:

Size of each packet of information = 1,500 bytes

Number of packets = P

Number of bytes of information = B

2. Let's answer the questions:

A. How many packets would be needed to transmit 30,000 bytes of information?

P = 30,000 ÷ 1,500

P = 20

<u>It would be needed 20 packets to transmit 30,000 bytes of information</u>

B. How much information could be transmitted in 30,000 packets?

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Note: Same answer provided to question 14037480, answered by me.

7 0
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