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3 years ago

Find the 99th term of the

Mathematics

1 answer:

Llana [10]3 years ago

6 0

Answer:

B) -350

Step-by-step explanation:

We are given the sequence:

-56, -59, -62, -65...

And we want to determine its 99th term.

First, note that we have an arithmetic sequence. This is because each subsequent term differs from the previous term by a common difference.

In this case, each subsequent term is 3 less than the previous term, so our common difference d is -3.

To find the 99th term, we can write an explicit formula. The explicit formula for an arithmetic sequence is:

$x_n=a+d(n-1)$

Where x_n represents the nth term, a is the initial term, and d is the common difference.

Since the first term is -56, a = -56.

By substitution, we acquire:

$x_n=-56-3(n-1)$

The 99th term is when n = 99. Thus:

$x_{99}=-56-3(99-1)$

Evaluate:

$x_{99}=-56-3(98)=-56-294=-350$

Our answer is B.

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Find the median of each set of data.

Tatiana [17]

Answer:

Step-by-step explanation:

Set 1: 12, 8, 6, 4, 10,1

Now find mean of 6 and 4:

(6+4)/2=10/2:

5 << answer of set 1

Set 2: 6,3,5, 11, 2, 9,5,0

(11+2)/2=6.5

Set 3: 30, 16, 49, 25

(16+49)=65/2

32.5

Sorry I was late to answer your question, but hope it helps!

Feel free to comment down below if you have any questions!

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4 years ago

Mrs. Smith has only 52.50 to spend at Old Navy. She wants to buy a shirt for Max that costs $39, including tax, and some socks t

Fynjy0 [20]

Answer:

Step-by-step explanation:

Let's find how much money is left if Mrs.Smith buys a shirt.

52.50 - 39 = 13.50

13.50/4.50 = s

s = 3

Hope this helps :)

6 0

3 years ago

In an arithmetic series, if the fifth term is 74 and the twelfth term is 116, find the sum of the first 30 terms.

Assoli18 [71]

If you know the formula of a given arithmetic series, it is (first term + last term)*(number of terms)/2. we already know we want the first 30 terms so number of terms = 30. now we should try to find the first and last term. we can do that by finding the d, or the distance between each successive term. this is:
(116 - 74)/(12 - 5) = 6.
now we can find the first term. the fourth term is 74 - 6, the third term is 74 - 2(6), the second term is 74 - 3(6) and the first term is 74 - 4(6) = 50.
now using the first term, we can find the last term. the last term is the 30th term and to get that number, some might think it is:
50 + 30(6)
but take a look at the second term, it is
50 + 6
and the third term, it is
50 + 2(6)
basically the nth term is
50 + (n-1)(6)
so the 30th term is:
50 + 29(6) = 224
now we can compute what we want:
(224 + 50)(30)/2 = 4110

now you may be wondering why the formula is the way it is. there is actually a story associated with this. there was a famous mathematician named carl friedrich gauss. legend has it that when he was a kid, once when he was in school, the teacher wanted to slack off, so he (or she...idk which one) told all his (her) students to add the numbers from 1 to 100. everyone instantly went 1+2 = 3, 3 + 3 = 6, 6 + 4 = 10, etc. carl, on the other hand, applied a neat trick that got him the answer really quickly. he wrote the integers from 1 to 100 then wrote that same sequence below it but in reverse order. so:
1, 2,   3, 4, 5, ...,   95, 96, 97, 98, 100
100, 99, 98, 97, 96, 95...5, 4 3, 2, 1
now add the first term of the top sequence to the first term of the bottom sequence (1 + 100 = 101), and do the same thing for the 2nd term of top and bottom sequence, and do it for all 100 terms. you'll find that each term adds to 101. so the total sum of the 2 identical sequences is (101)(100). the 101 is the first term+last term while the 100 is the number of terms (starting to look like the formula i proposed in the beginning!). now remember this is the sum of 2 sequences but we only want the sum of 1. since the sum of the 2 sequences are the same (because they have the same number but written in different orders) we can just take (101)(100) and divide that by 2 to get the sum of the first 100 positive integers. this can be extended to any arithmetic sequence like so:
a,   a+d, a+2d... a+(n-2)d, a+(n-1)d
a+(n-1)d, a+(n-2)d, ...a+d,   a
a is the first term of the sequence and d is the distance and the sequence has n terms. each of the n pairs sum to a + (a+(n-1)d) and we can do the same thing as carl did to get the formula i used to solve this problem.

let me know if you have any questions!!!

7 0

3 years ago

Solve for x. y = (5+x}m Answer?

Tanzania [10]

Answer:

x=ym−4

Step-by-step explanation:

y=(4+x)m

Here we have one equation with three unknowns. This cannot be "solved". We can only express one variable in terms of the other two.

Let's isolate x.

Divide through by m

ym=4+x

x=ym−4

(I really hope this helps)

4 0

3 years ago

You have two jobs. One job pays $7 per hour and the other pays $8.25 per hour. You worked 22 hours total last week and earned $1

il63 [147K]

X = 1st job
y = 2nd job

x + y = 22......x = 22 - y
7x + 8.25y = 171.50

7(22 - y ) + 8.25y = 171.50
154 - 7y + 8.25y = 171.50
-7y + 8.25y = 171.50 - 154
1.25y = 17.50
y = 17.50 / 1.25
y = 14 <== 14 hrs at the 8.25 per hr job

x + y = 22
x + 14 = 22
x = 22 - 14
x = 8 <=== 8 hrs at the 7 per hr job

8 0

3 years ago