Answer:
5
Step-by-step explanation:
The number of cells in a tile is 4, so the board dimension cannot be odd, but must be a multiple of 2 in order to have the number of cells divisible by 4.
If the tiles are colored in an alternating pattern, tiles must have 3 of one color and 1 of the alternate color. Hence the total number of tiles used to cover a board must be even (so the numbers of each color match). Then the board dimension must be divisible by 4.
In the given range, there are 5 such boards:
4×4, 8×8, 12×12, 16×16, and 20×20
Answer:
you’ve tried and have not won, Never stop for crying; All that’s good and great is done Just by patient trying. Though young birds, in flying, fall, Still their wings grow stronger, And the next time they can keep Up a little longer. Though the sturdy oak has known Many a wind that bowed her, She has risen again and grown Loftier and prouder. If by easy work you’re beat, Who the more will prize you? Gaining victory from defeat, That’s the test that tries you
<span>Is the following definition of perpendicular reversible? If
yes, write it as a true biconditional.</span>
Two lines that intersect at right angles are perpendicular.
<span>A. The statement is not reversible. </span>
<span>B. Yes; if two lines intersect at right
angles, then they are perpendicular.
</span>
<span>C. Yes; if two lines are perpendicular, then they intersect at
right angles. </span>
<span>D. Yes; two lines
intersect at right angles if (and only if) they are perpendicular.</span>
Your Answer would be (D)
<span>Yes; two lines
intersect at right angles if (and only if) they are perpendicular.
</span><span>REF: 2-3 Biconditionals and Definitions</span>
Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
Answer:
Your answer is
Fourth grade student = 25%
Fifth grade= 33.33%
Sixth grade= 41.67%
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