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babunello [35]
3 years ago
14

A soccer ball is at rest and is then kicked giving it a final velocity of 6.0 m/s. The ball has a mass of

Mathematics
1 answer:
Firdavs [7]3 years ago
3 0

Answer:

The average force applied to the ball is 84N

Step-by-step explanation:

This problem bothers on the impulse of a force

Given data

Mass of ball m= 0.28kg

Initial speed u= 0m/s

Final speed v= 6m/s

Time of impact t= 0.02s

We know that the impulse of a force

Ft= mv-mu

Hence the force is

F= (mv-mu)/t

F=m(v-u)/t

F= 0.28(6-0)0.02

F= 1.68/0.02

F= 84N

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1. Writing an equation for an exponential function by
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Answer: 1) t(n)=0.6(2)^n

2) f(x)=10(5)^x

Step-by-step explanation:

1) Let the function that shows the thickness of the paper after n folds,

t(n) = ab^n         ---------(1)

Since, According to the question,

Initially the thickness of the paper = 0.6

That is, at n = 0, t(0) = 0.6

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t(n) = 0.6 b^n       -----------(2)

Again when we fold the paper the thickness of the paper will be doubled.

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Thus, the complete function is,

t(n) = 0.6 (2)^n    

2) Let the function that is passing through the points (-2, 2/5) and (-1,2),

f(x) = ab^x         ---------(1)

For f(x) = 2, x = -1

By equation (1),

2= ab^{-1}       ---------(2)

Also, For f(x) = 2/5, x = -2

Again, By equation (1),

\frac{2}{5}= a(b)^{-2}

\implies \frac{2}{5}=ab^{-1}b^{-1}=2b^{-1}

\implies \frac{2}{5}=\frac{2}{b}

\implies 2b=10

\implies b = 5

By substituting this value in equation (2),

We get, a = 10

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