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Darya [45]
2 years ago
13

PLEASE ANSWER THIS, QUICK

Mathematics
2 answers:
Korvikt [17]2 years ago
6 0

Answer:

(x, y ) = ( - 3 , 14 )

Step-by-step explanation:

I hope this helps you. Best of luck.

babymother [125]2 years ago
4 0
Okay first you need to add both equations together

7x + 6y = 63
+ - 5x - 6y = -69
—————————
2x = -6

Then divide both sides

x = -3

Then plug -3 back into one of the equations to find y

7(-3) + 6y = 63
= -21 + 6y = 63
—-> 6y = 84

Divide both sides

y = 14

The answer is (-3, 14)
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Feliz [49]
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7 0
2 years ago
Which statements about the factors of the terms in the expression 20 a + 15 a b + 24 b are true? Select three options.
ExtremeBDS [4]

Answer:

Following are the true statements

2. The factors common to 20a and 15ab are 1, 5, and a.

3. The factors common to 20a and 24b are 1, 2, and 4.

5. The GCF of the expression is 1

Step-by-step explanation:

Expression is  20a + 15ab + 24b

Now lets have a look at each of the options provided!

1. The factors common to 20a and 15ab are 1, 5, a, and b.

False

As you can see there is no b in 20a term only 1,5,a are common hence it is false.

2. The factors common to 20a and 15ab are 1, 5, and a.

True

The terms 20a and 15ab are divisible by 1,5,a hence it is true.

3. The factors common to 20a and 24b are 1, 2, and 4.

True

The terms 20a and 24b are divisible by 1,2,4 hence it is true

4. The GCF of the expression is ab.

False

20a + 15ab + 24b

As you can see ab is not common in all of the terms hence it cannot be greatest common factor

5. The GCF of the expression is 1

True

Factor of 20 are: 2,2,5,1

Factor of 15 are: 3,5,1

Factor of 24 are: 2,2,2,3,1

As you can see the only common factor among all the terms is 1 hence GCF is 1.

5 0
3 years ago
3. 'a' and 'b' are the intercepts made
Julli [10]

Given:

'a' and 'b' are the intercepts made  by a straight-line with the co- ordinate axes.

3a = b and the line  pass through the point (1, 3).

To find:

The equation of the line.

Solution:

The intercept form of a line is

\dfrac{x}{a}+\dfrac{y}{b}=1         ...(i)

where, a is x-intercept and b is y-intercept.

We have, 3a=b.

\dfrac{x}{a}+\dfrac{y}{3a}=1           ...(ii)

The line  pass through the point (1, 3). So, putting x=1 and y=3, we get

\dfrac{1}{a}+\dfrac{3}{3a}=1

\dfrac{1}{a}+\dfrac{1}{a}=1

\dfrac{2}{a}=1

Multiply both sides by a.

2=a

The value of a is 2. So, x-intercept is 2.

Putting a=2 in b=3a, we get

b=3(2)

b=6

The value of b is 6. So, y-intercept is 6.

Putting a=2 and b=6 in (i), we get

\dfrac{x}{2}+\dfrac{y}{6}=1

Therefore, the equation of the required line in intercept form is \dfrac{x}{2}+\dfrac{y}{6}=1.

5 0
3 years ago
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