Length = w+3
P = 2L +2W
50 = 2(w+3) + 2w
50 = 2w +6 +2w
50 = 4w +6
50-6 =4w-6
44 = 4w
44/4 = 4w/4
w = 11
l = 11+3
l = 14
50 = 2L+2W
50 = 2(14) + 2(11)
50 = 28 +22
50=50
8*40 = 320 * 2 = $640 for the 2 workers
640/2000 = 0.32
labor cost is 32% of the revenue
Answer:
c
Step-by-step explanation:
Answer:
5 years
Step-by-step explanation:
In the question we are given;
- Amount invested or principal amount as $5048
- Rate of interest as 4% compounded 12 times per year
- Amount accrued as $6,163.59
We are required to determine the time taken for the money invested to accrue to the given amount;
Using compound interest formula;

where n is the interest period and r is the rate of interest, in this case, 4/12%(0.33%)
Therefore;



introducing logarithms on both sides;

But, 1 year = 12 interest periods
Therefore;
Number of years = 60.61 ÷ 12
= 5.0508
= 5 years
Therefore, it will take 5 years for the invested amount to accrue to $6163.59
Answer:
1 Chair= $1.25 1 table= $8.25
Step-by-step explanation:
5c+3t=31
2c+6t= 52
-2(5c+3t=31)
-10c-6t=-62
+
2c+6t=52
= -8c=-10
/-8 /-8
c= 1.25 or 1 1/4
2c+6t=52
2(1.25)+6t=52
2.5+6t=52
-2.5 -2.5
6t= 49.5
/6 /6
t= 8 1/4