Answer:
Mass = 26.50 g
Explanation:
Given data:
Mass of sodium carbonate = ?
Molarity of solution = 0.25 M
Volume of solution = 1.00 L
Solution:
Molarity = number of moles / volume in litter
0.25 M = number of moles / 1.00 L
Number of moles = 0.25 M × 1.00 L
Number of moles = 0.25 mol
Mass:
Mass = number of moles × molar mass
Mass = 0.25 mol × 106 g/mol
Mass = 26.50 g
Answer:
79.0 mL
Explanation:
Given data
- Initial concentration (C₁): 10.0 M
- Final concentration (C₂): 1.00 M
- Final volume (V₂): 790.0 mL
In order to find the volume required of the concentrated solution, we will use the dilution rule.
C₁ × V₁ = C₂ × V₂
V₁ = C₂ × V₂/C₁
V₁ = 1.00 M × 790.0 mL/10.0 M
V₁ = 79.0 mL
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