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suter [353]
3 years ago
7

A solid is 5 cm tall 3 cm wide and 2 cm thick it has a mass of 129 g what is the density

Chemistry
2 answers:
belka [17]3 years ago
7 0
First you would multiply 5,3, and 2 to get a volume of 30. Density is mass over volume so you would then divide 129 by 30. You would get 4.3. The answer would be 4.3 g/cm^3
dlinn [17]3 years ago
4 0

<u>Answer:</u> The density of solid is 4.3g/cm^3

<u>Explanation:</u>

To calculate the volume of cuboid, we use the equation:

V=lbh

where,

V = volume of cuboid

l = length of cuboid = 5 cm

b = breadth of cuboid = 3 cm

h = height of cuboid = 2 cm

Putting values in above equation, we get:

V=5\times 3\times 2=30cm^3

To calculate density of a substance, we use the equation:

Density=\frac{Mass}{Volume}

Putting values in above equation, we get:

\text{Density of solid}=\frac{129g}{30cm^3}\\\\\text{Density of solid}=4.3g/cm^3

Hence, the density of solid is 4.3g/cm^3

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Question 15 How many grams of NaCl are required to make 500.0 mL of a 1.500 M solution? 58.40 g 175.3 g 14.60 g 43.83 g
ExtremeBDS [4]
Hi!

To make 500 mL of a 1,500 M solution of NaCl you'll require 43,83 g

To calculate that, you will need to use a conversion factor to go from the volume of the 1,500 M solution to the required grams. For this conversion factor, you'll use the definition for Molar concentration (M=mol/L) and the molar mass of NaCl. The conversion factor is shown below:

gNaCl=500mLsol* \frac{1L}{1000 mL}* \frac{1,500 mol NaCl}{1Lsol}* \frac{58,4428 g NaCl}{1 mol NaCl} \\ =43,83gNaCl

Have a nice day!
4 0
3 years ago
Find the area of a triangle with a base of 4 meters and a height of 6 meters
RSB [31]

Answer:

24 meters

Explanation:

24 meter because area

area=Lxw

so just multiply 4 x 6 = 24

4 0
3 years ago
What is the temperature change that 725 g of aluminum will undergo when 2.35 x 104
Rashid [163]

Answer:

36°C

Explanation:

Given parameters:

Mass of aluminum = 725g

Quantity of heat  = 2.35 x 10⁴J

Unknown:

Temperature change  = ?

Solution:

To solve this problem, we simply use the expression below:

  The quantity of energy is given as:

          Q  = m C Δt

Q is the quantity of energy

m is the mass

C is the specific heat capacity of aluminum  = 0.9J/g°C

Δt is the change in temperature

  The unknown is Δt;

             Δt  = \frac{Q}{mc}    = \frac{2.35 x 10^{4} }{725 x 0.9}    = 36°C

5 0
3 years ago
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