180=51+2x+3+4x+8
180=51+11+6x
180=62+6x
-62 -62
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118=6x
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6x 6x
x=17
exterior angle = 4x+8
4(17) + 8
68 + 8
76
Complement of an angle = 90° - x.
Supplement of the complement of an angle = 180 - (90 - x).
= 180 - 90 + x
= 90 + x
Supplement of the complement of an angle less the complement of an angle = (90 + x) - (90 - x)
= 90 + x - 90 + x
= 2x
Now, the quotient of the supplement of the angle and the number 3 is
.
It is given that supplement of the complement of an angle less the complement of an angle exceeds the quotient of the supplement of the angle and the number 3 by 73.
Therefore, 2x = 

Multiply both sides by 3.
6x = 180 - x + 219
= 399 - x
Add x to both sides.
6x + x = 399
7x = 399
Divide both sides by 7.
x = 57
Hence, the required angle = 57°.
Y/x = 7/2
Cross multiply.
2y = 7x
Solve for y.
y = 7/2x
C) The slope of the line is 7/2
D) The y intercept is 0
6-by=19
minus 6 from both sides
-by=19-6
-by=13
divide both sides by -b
y=13/-b
y=-13/b