Answer:
b
Step-by-step explanation:
a^3b^2c = b(a^3bc)
5bc = b(5c)
15a^2b = b(15a^2)
GCF = b
The graph of the circle equation is graph (d)
<h3>How to determine the circle?</h3>
The equation is given as:
x^2 + y^2 - 4x + 9y -7 = 0
Rewrite as:
x^2 - 4x + y^2 + 9y = 7
Express (x^2 - 4x) and (y^2 + 9y) as perfect squares.
So, we have:
(x - 2)^2 + (y + 3)^2 = 7 + 4 + 20.25
Evaluate the sum
(x - 2)^2 + (y + 3)^2 = 31.25
A circle equation is represented as:
(x - h)^2 + (y - k)^2 = r^2
Where
Center = (h, k)
Radius = r
So, we have:
(h, k) = (2, -3)
r^2 = 31.25
r = 5.5
The circle that has a center of (2, -3) and a radius of 5.5 is graph d
Hence, the graph of the circle equation is graph (d)
Read more about circle equation at:
brainly.com/question/1559324
#SPJ1
(3 - i) + (1 - 2i)
= 3 + 1 - i - 2i
= 4 - 3i
Complete question:
y = 2x² + 2x - 3
x = -2 -1 0 1 2
Answer:
<u>Complete table of values</u>
x: -2 -1 0 1 2
y: 1 -3 -3 1 9
Step-by-step explanation:
Given;
y = 2x² + 2x - 3
To complete the table of values of the equation above, we substitute the value of x into the given equation and solve for y.
when, x = -2
y = 2(-2)² + 2(-2) - 3
y = 8 - 4 - 3
y = 1
when x = -1
y = 2(-1)² + 2(-1) - 3
y = 2 - 2 - 3
y = -3
when x = 0
y = 2(0)² + 2(0) - 3
y = 0 - 0 - 3
y = -3
when x = 1
y = 2(1)² + 2(1) - 3
y = 2 + 2 - 3
y = 1
when x = 2
y = 2(2)² + 2(2) - 3
y = 8 + 4 - 3
y = 9
<u>Complete table</u>
x: -2 -1 0 1 2
y: 1 -3 -3 1 9
If you're using the app, try seeing this answer through your browser: brainly.com/question/2787701_______________
Square both sides:
Since
is positive, you can discard the negative sign. So,
Substitute this value back into
to find
I hope this helps. =)
Tags: <em>trigonometric identity relation trig sine cosine tangent sin cos tan trigonometry precalculus</em>
