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DIA [1.3K]
3 years ago
6

Guys can you please help me on this one

Mathematics
1 answer:
algol133 years ago
8 0

Answer:Question 1 is C and B

Question 2 is 2

Question 3 is D

Step-by-step explanation:

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X^2+x-2/1-x^2 ÷ 2x^2-6x-20/x^2-4x-5
ad-work [718]
<span>X^2+x-2/1-x^2 ÷ 2x^2-6x-20/x^2-4x-5

   (x + 2)(x - 1)           (x - 5)(x + 1)
= ------------------- *  ---------------------
   (1 + x)(1- x)           2(x + 2)(x - 5)

</span>    (x - 1)        
= ----------
   2(1- x)    

    - (1 - x)        
= -------------
     2(1 - x)    

= -1/2

answer
-1/2 
   
7 0
4 years ago
Ill give you brainliest&gt;&gt;&gt;Write an equation of the line passing through the point (5, 2) that is perpendicular to the l
11Alexandr11 [23.1K]

y= mx+b

(16, -7) = (x,y)

2(16) - 3y = 12

32 - 3y = 12

32 - 12 = 3y

20/3 = y

6.6 = y

2x-3(-7) = 12

2x+21 = 12

2x = 12 - 21

x = -9/2

Insert the values into y = mx + b

solve for m and then solve for b

6 0
3 years ago
How to convert from rectangular to polar coordinates pre calc?
Verizon [17]
<span>Given the polar coordinate (r,θ), write. x=rcos θ and. y=rsin θ.Evaluate cos θ and. sin θ.Multiply cos θ by. r. to find the x-coordinate of the rectangular form.<span>Multiply sin θ by. r. to find the y-coordinate of the rectangular form.</span></span>
6 0
3 years ago
A nutritionist would like to estimate the number of times adults exercise each week. To collect information, the nutritionist em
enot [183]

Answer:

Step-by-step explanation:

c

7 0
3 years ago
2.- Supóngase que los diámetros de los tornillos fabricados por una compañía están distribuidos normalmente con una media de 0.2
Sergio [31]

Answer:

7.30167%

Step-by-step explanation:

Usando la fórmula de puntuación z

z = (x-μ) / σ, donde x es la puntuación bruta, μ es la media de la población y σ es la desviación estándar de la población

Para x <0.20 pulgadas

z = 0.20 - 0.25 / 0.02

z = -2.5

Valor de probabilidad de Z-Table:

P (x <0.20) = 0.0062097

Para x> 0.28 pulgadas

z = 0.28 - 0.20 / 0.02

z = 1.5

Valor de probabilidad de Z-Table:

P (x <0.28) = 0.93319

P (x> 0.28) = 1 - P (x <0.28) = 0.066807

La probabilidad de que se produzcan tornillos defectuosos cuando el tornillo se considera defectuoso si su diámetro es inferior a 0.20 pulgadas o superior a 0.28 pulgadas es

P (x <0.20) + P (x> 0.28)

= 0.0062097 + 0.066807

= 0.0730167

Conversión a porcentaje

= 0.0730167 × 100

= 7.30167%

El porcentaje de tornillos defectuosos producidos es

7.30167%

3 0
3 years ago
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