Using the normal distribution, it is found that Sue will get a letter grade of B.
In a <em>normal distribution </em>with mean 
and standard deviation 
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem, Sue got a grade of 0.85, hence 
.
- Looking at the z-table, z = 0.85 has a p-value of 0.8023, hence she is approximately in the top 20%, which is below the top 15% but above the top 50%, hence she got a letter grade of B.
A similar problem is given at brainly.com/question/25745464
Answer:
-0.3
Step-by-step explanation:
i don't really have an explanation i just know
You would put 9 times v because you are multiplying it to the 9 and you do not know what v is then you would divide it by 3 and get your answer so for example if you should have gotten 9 times v = 72 then 72 divided by 3 = 24 and 24 divided by 3 = 8
Answer:
-2, -6
Step-by-step explanation:
using cramer rule
5 -3
-2 -1
calculatiing the determinant = (5 x-1) - (-3x-2) = -5 -(6) = -5-6=-11
using cramer rule
to calculate x we change the coefficient of x with the answer (8,10)
8 -3
10 -1
we calculate determinant = (8x-1)-(-3x10) = -8-(-30) = -8+30 =22
to calculate x
22/-11= -2
to calculate y we change the coefficient of y with the answer (8,10)
5 8
-2 10
we calculate determinant = (5x10)-(8x-2) = 50 -(-16) = 50 +16=66
to calculate y
66/-11= -6
