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Doss [256]
3 years ago
9

This is a test get it right I want a good grade

Mathematics
1 answer:
Fittoniya [83]3 years ago
7 0

Answer:

\frac{120}{6} \geq \frac{200}{8}      \frac{120}{6} is the better unit price.

Step-by-step explanation:

120 is the better unit price because if you divide 120 divided by 6 you get 20 and if you divide 200 divided by 8 you get 25 so then you would pick the cheapest one because of its price and amount.

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Step-by-step explanation:

The question states 25 push-ups plus x amount of push-ups per day. To find how many push-ups per week, we multiply how many push-ups per day by 7 (a week).

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3 years ago
If f(x) = 2x ^ 2 + 5 squreroot(x - 2) complete the following statement
lubasha [3.4K]

Answer:

hello :

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f(x) = 2x²+5√(x-2)

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7 0
2 years ago
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
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